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Reika [66]
3 years ago
14

A bakery sells cakes, cookies, and pastries. They wonder if customers are equally likely to buy each product. They take a sample

of 200 recent purchases and record what was purchased (they are willing to treat this as a random sample). Here are the results
Product Cakes Cookies Pastries
Observed purchases 65 68 67

They want to perform a x^2 goodness-of-fit test to determine if these results suggest that one type of product is more popular than the others. What is the expected count of cake purchases?
Mathematics
1 answer:
Katena32 [7]3 years ago
3 0

Answer:

66.667 cakes

Step-by-step explanation:

The expected count or value in a goodness of fit test is the product of the expected percentage and the total count or sample size.

Since the samples are being treated as a random sample, hence, the expected percentage of each of cake, pastries and cookies is the same.

The expected count of cakes is :

100/3 % * sample size

33.3333% * 200

= 66.667 cakes

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Which pair of funtions is not a pair of inverse functions? please help!!
antiseptic1488 [7]

Answer:

f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

<u>case A)</u> f(x)=\frac{x+1}{6} , g(x)=6x-1

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y+1}{6}

Isolate the variable y

6x=y+1

y=6x-1

Let

f^{-1}(x)=y

f^{-1}(x)=6x-1

therefore

f(x) and g(x) are inverse functions

<u>case B)</u> f(x)=\frac{x-4}{19} , g(x)=19x+4

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y-4}{19}

Isolate the variable y

19x=y-4

y=19x+4

Let

f^{-1}(x)=y

f^{-1}(x)=19x+4

therefore

f(x) and g(x) are inverse functions

<u>case C)</u> f(x)=x^{5}, g(x)=\sqrt[5]{x}

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=y^{5}

Isolate the variable y

fifth root both members

y=\sqrt[5]{x}

Let

f^{-1}(x)=y

f^{-1}(x)=\sqrt[5]{x}

therefore

f(x) and g(x) are inverse functions

<u>case D)</u> f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y}{y+20}

Isolate the variable y

x(y+20)=y

xy+20x=y

y-xy=20x

y(1-x)=20x

y=20x/(1-x)

Let

f^{-1}(x)=y

f^{-1}(x)=20x/(1-x)

\frac{20x}{1-x}\neq \frac{20x}{x-1}

therefore

f(x) and g(x) is not a pair of inverse functions

7 0
3 years ago
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mina [271]
( 12 + 7) 5x = 95 so that's your answer
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What is the sum of the series? ​ 5∑i=1 4i ​
Svetlanka [38]

Answer:

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Answer:

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Step-by-step explanation:

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YO please help actually been waiting for an hour and a half cuz so many trolls lol. &lt;3 giivng brainliest, and ty in advance g
kati45 [8]

Hello!

For this problem we are given that quadrilateral ABCD is congruent to quadrilateral GJIH, meaning that all sides and angle measures will be equivalent to its corresponding side.

This means that to find x, we can look at quadrilateral GJIH's corresponding side to quadrilateral ABCD's side AD, which is side GH, which has a value of 9.

This means that 9 should also be the side length of side AD, which we're given a value of x/3.

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x=27

Hope this helps!

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3 years ago
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