Hello there!
3x - y = 3
-x + y = 3
We need to solve 3x - y = 3 for y
Let start by adding -3x to both sides
3x - y = 3
3x - 3x - y = 3 - 3x
-y = 3 - 3x
We cannot leave the variable with a negative sign. We must multiply both sides by -1
-y * -1= (3 - 3x)-1
y = 3x - 3
Substitute 3x -3 for y in -x+y=3
-x + y = 3
-x + 3x - 3 = 3
2x - 3 = 3
2x = 3 + 3
2x = 6
x = 6/2
x = 3
Now substitute 3 for x in y=3x -3
y = 3x - 3
y = 3(3) - 3
y= 9 - 3
y= 6
Thus,
The answer is x=3 and y=6
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The <em>twelfth</em> element of the <em>geometric</em> sequence is equal to 4,096. (Correct choice: D)
<h3>How to find a determined element of a geometric sequence by exponential formulae</h3>
Sequences are series of elements generated according to at least one condition, usually equations. <em>geometric</em> sequences are generated according to a <em>exponential</em> formulas, whose form and characteristics are described below:
f(n) = a · bⁿ ⁻ ¹ (1)
Where:
- a - First element of geometric sequence
- b - Common ratio of the geometric sequence
- n - Element index within the geometric sequence
If we know that a = 4, b = 2 and n = 12, then the twelfth element of the geometric sequence from the statement is:
f(12) = 4 · 2¹² ⁻ ¹
f(12) = 4 · 2¹¹
f(12) = 4 · 2,048
f(12) = 4,096
The <em>twelfth</em> element of the <em>geometric</em> sequence is equal to 4,096. (Correct choice: D)
To learn more on geometric sequences: brainly.com/question/4617980
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Answer:
Step-by-step eWrite 2.9 as
2.9
1
Multiply both numerator and denominator by 10 for every number after the decimal point
2.9 × 10
1 × 10
=
29
10
Reducing the fraction gives
29
10xplanation:
Hello.
To get the volume 5184 in3 you can use the dimension 18in x 24in x 12in.
First, you should draw a picture of your shipping container. It is a rectangular prism that is 5 by 12 by 4.
Next, let's look at the boxes of apples that will go into the box. The volume has to be 5184 in^3. If we divide it by 12 and 12, the answer is 3. Therefore, we could make a box that is 1 foot by 1 foot by 3 feet.
Those boxes would be stack on the base without any left over space. Now, just figure out how many would go on the next rows. They would be able to stand up and down.
Have a nice day.
