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kotykmax [81]
3 years ago
7

The scale on a map is 2cm= 1km. Express this as a ratio

Mathematics
1 answer:
Lemur [1.5K]3 years ago
7 0
This would mean that the ratio is 2:1 or 2 to 1 or also 2/1.

The ratio would be that because it's 2 centimeters per 1 kilometer.
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A student ran 100 m dash in 15.4 seconds. What was the student speed in miles per hour
amid [387]

15.4 seconds = 0.00428 hours and 100 meters = 0.062 miles soo the student ran approximately 14.5 mph

8 0
3 years ago
There are 412 students and 20 teachers taking buses on a trip to a museum. Each bus can seat a maximum of 48. Which inequality g
Vlad1618 [11]

Answer:

Option B. b\geq 9

Step-by-step explanation:

Let

b------> the number of buses

we know that

48b\geq (412+20) -----> inequality that represent the situation

Solve for b

48b\geq 432

b\geq 432/48

b\geq 9

6 0
3 years ago
Read 2 more answers
the area of a right triangle is 336 square centimeters. The base of the right triangle is 48 centimeters. What is the length of
Alex73 [517]

Answer:

50 cm

Step-by-step explanation:

So the first step is to find the height, and to do that you know that the area of a triangle is height * base / 2 =  area. Plugging in the numbers you have, you get:

height*48/2=336

Then, this becomes

height * 24 = 336

Divide both sides by 24

height = 14

Now you can use the base and the height to find the hypotenuse using the Pythagorean Theorem: a^{2} +b^{2} =c^{2}

48^{2} +14^{2} =c^{2} \\2304 + 196 = c^{2}\\2500 = c^2\\50 = c\\c = 50

Therefore the length of the hypotenuse is 50 cm

8 0
3 years ago
The second of two numbers is 8 less than twice the first number, what are the two numbers?
Mashutka [201]
So the two numbers can be represented as x and y

so x is first and y is second

y=2(x)-8

so y=2x-8


IF THEY ARE CONSECUTIVE
If they are consecutive numbers then 
x+1=y
subtitute
x+1=2x-8 
subtract x from both sides
1=x-8
add 8 to both sides and get
9=x
put it into the equation and get
y=2(9)-8
y=18-8
y=10
so x=9
y=10 
IF X AND Y ARE CONSECUTIVE INTEGERS (1,2,3,4 not 2.3 or 1,3,5,8)

3 0
4 years ago
Read 2 more answers
Show that the roots of the equations
harkovskaia [24]

Answer:

The roots are real and distinct.

Step-by-step explanation:

Given the following equation:

x^{2} + kx - k -2 =0

In this problem, a = 1, b = k and c = -k - 2

The discriminant is b² - 4ac, and for the roots to be real and distinct, it must be at least or greater than 0.

We get,

(k)²- 4(1)(-k - 2) = 1 - 4(-k - 2)

= k² + 4k + 8

Let's check:

At k = -2,

(-2)^{2} + 4(-2) + 8 = 4 - 8 + 8 = 4




At k = 0,

(0)^2 + 4(0) + 8 = 8

At k = -100,

(-100)^2 + 4(-100) + 8 = 10,000 - 400 + 8 = 9608

Therefore, we can conclude that for all values of k, the roots are real and distinct.

This has been a long way in answering this question, so it would be great if you could mark me as brainliest

3 0
3 years ago
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