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zubka84 [21]
3 years ago
10

What are the advantages of customer relationship managment​

Computers and Technology
1 answer:
Delvig [45]3 years ago
3 0

Answer:

Enhances Better Customer Service.

Facilitates discovery of new customers.

Increases customer revenues.

Helps the sales team in closing deals faster.

Enhances effective cross and up-selling of products.

Simplifies the sales and marketing processes.

Makes call centers more efficient.

Enhances customer loyalty.

You might be interested in
List safety conditions when downloading shareware, free free where, or public domain software
Anit [1.1K]

Answer:

Explanation:

Freeware and shareware programs are softwares which are either free of charge or consist of a free version for a certain trial period. These programs pose a threat of habouring malware or viruses which could damage one's computer and important files and programs. Therefore, it is imperative that carefulness is maintained when trying to get these softwares.

Some of the necessary safety conditions that should be taken include;

1) Appropriate research about the software including taking more about the vendors and reviews.

2.) Once, a healthy review has been identified ; the download can begin with the Downloader ensuring that the download is from the recommended site.

3) Prior to installation the software should be scanned with an active anti-virus program to determine if there is possibility that a virus has creeped in.

4.) Some softwares may require that computer anti-virus be turned off during installation, this is not always a good idea as this act leaves the system vulnerable a d badly exposed.

6 0
2 years ago
What two methods can be used to access and modify an existing program that is running on an iot device in cisco packet tracer? (
dsp73

Cisco Packet Tracer is tool used for network simulation and visualization program.

The two methods can be used to access and modify an existing program that is running on an IoT device in Cisco packet trace are the following:

1. Click on the device then select the Programming tab.

2. Go to the registration server and login. Then select the Editor tab.

3 0
3 years ago
after a few weeks of using facial recognition login, your infrared camera fails, and you are asked to enter your pin. because it
riadik2000 [5.3K]

The reason that you have not been locked out after several failed PIN login attempts is that your laptop does not have a TPM chip, and you have not set up BitLocker for lockout.

Technology known as Trusted Platform Module (TPM) is made to offer hardware-based, security-related functionality. Designed to perform cryptographic operations, a TPM chip is a safe crypto-processor. Malicious software cannot interfere with the TPM's security capabilities, and the chip has numerous physical security features to prevent tampering. Utilizing TPM technology has a number of major benefits, including the following:

  • Cryptographic keys should be created, stored, and used sparingly.
  • Utilize the burnt-in RSA key of the TPM to authenticate platform devices using TPM technology.
  • By recording security metrics, you can assist in ensuring platform integrity.

To learn more about TPM click here:

brainly.com/question/10742732

#SPJ4

7 0
9 months ago
Create a program which will input data into a pipe one character at a time. Count the number of characters as they are written i
LenKa [72]

Answer:

a)

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

 

#define BUFSIZE 16

int main(){

   //pipe descriptors

   char msg[BUFSIZE];

   char buf[BUFSIZE];

   int pipefd[2];

   if(pipe(pipefd) == -1){

       //pipe creation error

       perror("pipe");

       exit(EXIT_FAILURE);

   }

   //pipe creation successfull

   //write four messages

   sprintf(msg , "apple");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   sprintf(msg , "boy");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   sprintf(msg , "cat");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   sprintf(msg , "dog");

   write(pipefd[1], msg, BUFSIZE);

   printf("Written %s\n", msg);

   //read

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   read(pipefd[0], buf, BUFSIZE);

   printf("Read: %s\n", buf);

   close(pipefd[0]);

   close(pipefd[1]);

   return 0;

}

(b)

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

#include<wait.h>

#define BUFSIZE 16

int main(){

   //pipe descriptors

   char msg[BUFSIZE];

   char buf[BUFSIZE];

   int pipefd[2];

   if(pipe(pipefd) == -1){

       //pipe creation error

       perror("pipe");

       exit(EXIT_FAILURE);

   }

   //pipe creation successfull

   //write four messages

   if(fork() == 0){

       //this is child

       //close unused write end

       close(pipefd[1]);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading first message. Content is %s\n", buf);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading second message. Content is %s\n", buf);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading third message. Content is %s\n", buf);

       read(pipefd[0], buf, BUFSIZE);

       printf("This is child process reading fourth message. Content is %s\n", buf);

       close(pipefd[0]);

       //exit from child

       exit(EXIT_SUCCESS);

   }

   //this is parent process

   //close unused read end

   close(pipefd[0]);

   sprintf(msg , "apple");

   printf("This is parent process. Writing first message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   sprintf(msg , "boy");

   printf("This is parent process. Writing second message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   sprintf(msg , "cat");

   printf("This is parent process. Writing third message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   sprintf(msg , "dog");

   printf("This is parent process. Writing fourth message into pipe\n");

   write(pipefd[1], msg, BUFSIZE);

   close(pipefd[1]);

   //wait for child

   wait(NULL);

   return 0;

}

(c)

#include<stdio.h>

#include<stdlib.h>

#include<fcntl.h>

#include<unistd.h>

#include<sys/wait.h>

#include<sys/types.h>

#include<signal.h>

typedef struct sigaction Sigaction;

unsigned long long size = 0;

void alarmhandler(int sig){

   //alarm fired writing blocked

   printf("Write blocked after %llu characters\n", size);

   exit(EXIT_SUCCESS);

}

int main(){

   //pipe descriptors

   int pipefd[2];

   if(pipe(pipefd) == -1){

       //pipe creation error

       perror("pipe");

       exit(EXIT_FAILURE);

   }

   //install handler

   sigset_t mask , prev;

   sigemptyset(&mask);

   sigaddset(&mask , SIGALRM);

   sigprocmask(SIG_BLOCK , &mask , &prev);

   Sigaction new_action;

   sigemptyset(&new_action.sa_mask);

   new_action.sa_flags = SA_RESTART;

   new_action.sa_handler = alarmhandler;

   sigaction(SIGALRM , &new_action , NULL);

   sigprocmask(SIG_SETMASK , &prev, NULL);

   while(1){

     

       //print size on multiple of 4

       if(size != 0 && size % 1024 == 0){

           printf("%llu characters in pipe\n", size);

       }

       //reset previous alarm

       alarm(0);

       //set new alarm for 5 seconds

       alarm(5);

       //write to pipe one character

       write(pipefd[1], "A", sizeof(char));

       size++;

   }

   return 0;

}

Explanation:

Output for a, b, c are pasted accordingly

4 0
3 years ago
Which block cipher mode of operating requires that both the message sender and receiver access a counter that computes a new val
ankoles [38]

There is block cipher kind of mode of operation. The block cipher mode of operating requires that both the message sender and receiver  is exchanged is the (CTR) Counter.

<h3>What is the Counter (CTR)?</h3>

This is known to be a common block cipher mode of operation. It often needs that both the message sender and receiver to have a kind of access a counter, that helps to computes a new value whenever a ciphertext block is been exchanged.

The disadvantage of CTR is known to be the fact that it needs a synchronous counter necessary for both the sender and receiver.

Learn more about  block cipher mode from

brainly.com/question/9979590

7 0
1 year ago
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