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Olin [163]
3 years ago
14

Think back over the information presented in the lesson about how you can skillfully use the Internet when doing research. Selec

t three of the ideas that you think are particularly useful for you and other students to know. In a paragraph of not less than five sentences, explain which ideas you picked and why.
more points!
Computers and Technology
1 answer:
madreJ [45]3 years ago
7 0

Avoid wikipedia, anyone can put answers down on there and make it seem correct but it is not. Do not trust any website research the websites or look at ratings if possible. Use the answers that google provides itself if possible. And research trusted websites.

If this helped please mark me as brainlest.

\left[\begin{array}{ccc}Thanks,\\JustSomeIdiot\end{array}\right]

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The full meaning of ENIAC,ABACUS,EDVAC,EDSAC<br>and explain ​
balandron [24]

Answer:

ENIAC: Electronic Numerical Integrator and Computer.

ABACUS: Abundant Beads, Addition and Calculation Utility System.

EDVAC: Electronic Discrete Variable Automatic Computer

EDSAC: Electronic Delay Storage Automatic Computer

7 0
3 years ago
Which statement is false? Select one: a. A class is to an object as a blueprint is to a house. b. Classes are reusable software
kow [346]

Answer:

A class is an instance of its object

Explanation:

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application that will perform a lot of overwrites and deletes of data and requires the latest information to be available anytim
o-na [289]

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RDS.

Explanation:

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3 0
3 years ago
Fifty-three percent of U.S households have a personal computer. In a random sample of 250 households, what is the probability th
aleksley [76]

Answer:

The correct Answer is 0.0571

Explanation:

53% of U.S. households have a PCs.

So, P(Having personal computer) = p = 0.53

Sample size(n) = 250

np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10

So, we can just estimate binomial distribution to normal distribution

Mean of proportion(p) = 0.53

Standard error of proportion(SE) =  \sqrt{\frac{p(1-p)}{n} } = \sqrt{\frac{0.53(1-0.53)}{250} } = 0.0316

For x = 120, sample proportion(p) = \frac{x}{n} = \frac{120}{250} = 0.48

So, likelihood that fewer than 120 have a PC

= P(x < 120)

= P(  p^​  < 0.48 )

= P(z < \frac{0.48-0.53}{0.0316}​)      (z=\frac{p^-p}{SE}​)  

= P(z < -1.58)

= 0.0571      ( From normal table )

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A start-up is expanding overseas and spends an excessive amount of time on recruiting and hiring activities, hindering its abili
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HCM is a word for Human Capital Management
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