Think back over the information presented in the lesson about how you can skillfully use the Internet when doing research. Selec
1 answer:
Avoid wikipedia, anyone can put answers down on there and make it seem correct but it is not. Do not trust any website research the websites or look at ratings if possible. Use the answers that google provides itself if possible. And research trusted websites.
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Answer:
The correct Answer is 0.0571
Explanation:
53% of U.S. households have a PCs.
So, P(Having personal computer) = p = 0.53
Sample size(n) = 250
np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10
So, we can just estimate binomial distribution to normal distribution
Mean of proportion(p) = 0.53
Standard error of proportion(SE) = =
= 0.0316
For x = 120, sample proportion(p) = =
= 0.48
So, likelihood that fewer than 120 have a PC
= P(x < 120)
= P( p^ < 0.48 )
= P(z < ) (z=
)
= P(z < -1.58)
= 0.0571 ( From normal table )