5/30 were absent or 1/6 simplifying or dividing both by 5 we have: 1/6
Answer:
Step-by-step explanation:
3x2x2=12
5x7x3=105
Answer:
P43=4!(4–3)!=241=24
Step-by-step explanation:
There are four choices you can make for the lead reindeer. For each possible choice, there are then three remaining you can choose to fly second, making 4×3=12 choices for the lead pair. For each possible choice there are two remaining reindeer to take up the back position, making 12×2=24 choices for the team of three.
This type of problem is called a permutation problem, and we write Pnr for the number of ways of choosing r items from n possibilities when the order of the items matters. In this case we are choosing 3 reindeer from 4 possibilities, and the order they appear in the flying line does matter, so the answer we want is P43. The general formula is Pnr=n!(n−r)!. For the answer we are looking for we therefore have:
P43=4!(4–3)!=241=24
Answer:
I think they're both always but I'm not sure
Answer:
y=-2x-3
the line is going downwards which makes the slop a negative value
Step-by-step explanation:
