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miss Akunina [59]
3 years ago
11

I will give Brainiest if you are right

Mathematics
2 answers:
liberstina [14]3 years ago
4 0

Answer:

J is the answer ............

il63 [147K]3 years ago
4 0

Answer:

The answer is G.

Step-by-step explanation:

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WILL MARK BRAINLIEST NEED IT ASAP
myrzilka [38]

Answer:

8

Step-by-step explanation:

6 x 9=54. 54+10=64. the square root of 64 = 8

8 0
3 years ago
Read 2 more answers
An airplane travels 6111 kilometers against the wind in 9 hours and 7911 kilometers with the wind in the same amount of time. Wh
natima [27]

Answer:

Speed of the plane in still air: 779\; {\rm km \cdot h^{-1}}.

Windspeed: 100\; {\rm km \cdot h^{-1}}.

Step-by-step explanation:

Assume that x\; {\rm km \cdot h^{-1}} is the speed of the plane in still air, and that y\; {\rm km \cdot h^{-1}} is the speed of the wind.

  • When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be (x - y)\; {\rm km \cdot h^{-1}}.
  • When this plane is travelling in the same direction as the wind, the ground speed of this plane would be (x + y)\; {\rm km \cdot h^{-1}}.

The question states that when going against the wind (v = (x - y)\; {\rm km \cdot h^{-1}},) the plane travels 6111\; {\rm km} in 9\; {\rm h}. Hence, 9\, (x - y) = 6111.

Similarly, since the plane travels 7911\; {\rm km} in 9\; {\rm h} when travelling in the same direction as the wind (v = (x + y)\; {\rm km \cdot h^{-1}},) 9\, (x + y) = 7911.

Add the two equations to eliminate y. Subtract the second equation from the first to eliminate x. Solve this system of equations for x and y: x = 779 and y = 100.

Hence, the speed of this plane in still air would be 779\; {\rm km \cdot h^{-1}}, whereas the speed of the wind would be 100\; {\rm km \cdot h^{-1}}.

3 0
1 year ago
Find the mode of this set of data 18,27,28,44,44,50,67
8_murik_8 [283]

Answer:

44

Step-by-step explanation:

the mode of a set of data is the value that occurs most often, in this case it is 44

8 0
3 years ago
Read 2 more answers
Suppose you can factor x^2 +bx +c as (x+p)(x+q) . If c<0, what could be the possible values of p and q?
Anna11 [10]
Ans: Option A

Explanation:
Let's solve it smartly!
Given expression: x^{2} + bx +c --- (A)
Factors: (x+p)(x+q)
Condition: c<0
Now let us expand (x+p)(x+q):
=> x^{2} + (p+q)x + pq  --- (B)

By comparing (B) with (A), we can say that:
pq = c --- (C)

Now, as the condition says, c<0, it means either p or q is negative. Both cannot be positive or both cannot be negative.

1) If p>0, q>0, it means c>0 since (+p)(+q) = (+c)(according to equation (C)). Condition is not met.
Hence, option B and D are wrong.

2) If p<0, q<0 it means c>=0 since (-p)(-q) = (+c)(according to equation (C)). Condition is not met.
Hence option C is out as well.

We are left with Option A:p<0, q>0 it means c<0 since (-p)(+q) = (-c)(according to equation (C)).
Condition is MET!
Hence,
Ans: Option A: p= -3, q= 7
4 0
3 years ago
Read 2 more answers
Which data set is MOST LIKELY to be normally distributed?
mart [117]

Answer:a

Step-by-step explanation:

Doing it now on usatestprep

6 0
3 years ago
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