2 years ago

How to solve x^2>4x+3

1 answer:

7 0

Treat this as you would the quadratic equation x^2 - 4x - 3 + 0. Solve this by completing the square:

x^2 - 4x + 4 - 4 - 7 = 0

(x^2 - 4x + 4) = 11

(x-2)^2 = 11, and so x-2 = plus or minus sqrt(11).

Graph this, using a dashed curve (not a solid curve). Then shade the coordinate plane ABOVE the graph.

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