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schepotkina [342]
3 years ago
14

Constant of proportionality characteristics what are some?

Mathematics
1 answer:
Aleks [24]3 years ago
8 0

Answer: The constant of proportionality is the ratio between two directly proportional quantities.

Two quantities are directly proportional when they increase and decrease at the same rate.

Step-by-step explanation:

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To estimate the quotient 98.3 divides by 52.6 Brady used compatible numbers 100 dived by 5 =20. Is his estimate reasonable ? Exp
marissa [1.9K]
No, not reasonable.

98.3 divides by 52.6

Brady used compatible numbers 100 divided by 5 =20

He should've used 100 divided by 50 = 2
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4 years ago
What is the prime factorization of - 96
denis-greek [22]
There isn't a prime factorization of -96
8 0
3 years ago
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Solve the following equation algebraically: 3 x squared = 375 a. x almost-equals 49 b. x almost-equals plus-or-minus 49 c. x alm
d1i1m1o1n [39]
3x^2=375
x^2=125
x=11.18

c or d, they say the same thing
4 0
3 years ago
Solve this thing pls<br> <img src="https://tex.z-dn.net/?f=3%5Cleft%28q-7%5Cright%29%3D27" id="TexFormula1" title="3\left(q-7\ri
evablogger [386]

Answer:

  • Solution of equation ( q ) = <u>1</u><u>6</u>

Step-by-step explanation:

In this question we have given an equation that is <u>3 </u><u>(</u><u> </u><u>q </u><u>-</u><u> </u><u>7</u><u> </u><u>)</u><u> </u><u>=</u><u> </u><u>2</u><u>7</u><u> </u>and we have asked to solve this equation that means to find the value of <u> </u><u>q</u><u> </u><u>.</u>

<u>Solution : -</u>

\quad \: \longmapsto \:  3(q - 7) = 27

<u>Step </u><u>1</u><u> </u><u>:</u> Solving parenthesis :

\quad \: \longmapsto \:3q - 21 = 27

<u>Step </u><u>2</u><u> </u><u>:</u> Adding 21 on both sides :

\quad \: \longmapsto \:3q -  \cancel{ 21} +  \cancel{21} = 27  +  21

On further calculations we get :

\quad \: \longmapsto \:3q = 48

<u>Step </u><u>3 </u><u>:</u> Dividing by 3 from both sides :

\quad \: \longmapsto \: \frac{ \cancel{3}q}{ \cancel{3}}  =  \cancel {\frac{48}{3} }

On further calculations we get :

\quad \: \longmapsto \:   \pink{\boxed{\frak{q = 16}}}

  • <u>Therefore</u><u>,</u><u> </u><u>solution</u><u> </u><u>of </u><u>equation</u><u> </u><u>(</u><u> </u><u>q </u><u>)</u><u> </u><u>is </u><u>1</u><u>6</u><u> </u><u>.</u>

<u>Verifying</u><u> </u><u>:</u><u> </u><u>-</u>

Now we are very our answer by substituting value of q in the given equation . So ,

  • 3 ( q - 7 ) = 27

  • 3 ( 16 - 7 ) = 27

  • 3 ( 9 ) = 27

  • 27 = 27

  • L.H.S = R.H.S

  • Hence, Verified.

<u>Therefore</u><u>,</u><u> </u><u>our </u><u>solution</u><u> </u><u>is </u><u>correct</u><u> </u><u>.</u>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
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3 years ago
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Type the correct answer in each box. Use numerals instead of words.
Alex_Xolod [135]

Answer:


Step-by-step explanation:

Given that prices for a pair of shoes lie in the interval

[80,180] dollars.

Delivery fee 20% of price.  

i.e. delivery fee will be in the interval [4, 9]

(1/20th of price)

Total cost= price of shoedelivery cost

Hence f(c) = c+c/20 = 21c/20

The domain of this function would be c lying between 80 to 180

So domain =[80,180]

---------------------------------

Amount to be repaid = 42 dollars

Once he received this amount, the price would be

105+42 =147

But since price range is only [21*80/20, 21*180/20]

=[84, 189]

Since now Albert has 147 dollars, he can afford is

[80,147]




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3 years ago
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