No, not reasonable.
98.3 divides by 52.6
Brady used compatible numbers 100 divided by 5 =20
He should've used 100 divided by 50 = 2
There isn't a prime factorization of -96
3x^2=375
x^2=125
x=11.18
c or d, they say the same thing
Answer:
- Solution of equation ( q ) = <u>1</u><u>6</u>
Step-by-step explanation:
In this question we have given an equation that is <u>3 </u><u>(</u><u> </u><u>q </u><u>-</u><u> </u><u>7</u><u> </u><u>)</u><u> </u><u>=</u><u> </u><u>2</u><u>7</u><u> </u>and we have asked to solve this equation that means to find the value of <u> </u><u>q</u><u> </u><u>.</u>
<u>Solution : -</u>

<u>Step </u><u>1</u><u> </u><u>:</u> Solving parenthesis :

<u>Step </u><u>2</u><u> </u><u>:</u> Adding 21 on both sides :

On further calculations we get :

<u>Step </u><u>3 </u><u>:</u> Dividing by 3 from both sides :

On further calculations we get :

- <u>Therefore</u><u>,</u><u> </u><u>solution</u><u> </u><u>of </u><u>equation</u><u> </u><u>(</u><u> </u><u>q </u><u>)</u><u> </u><u>is </u><u>1</u><u>6</u><u> </u><u>.</u>
<u>Verifying</u><u> </u><u>:</u><u> </u><u>-</u>
Now we are very our answer by substituting value of q in the given equation . So ,
<u>Therefore</u><u>,</u><u> </u><u>our </u><u>solution</u><u> </u><u>is </u><u>correct</u><u> </u><u>.</u>
<h2>
<u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
Answer:
Step-by-step explanation:
Given that prices for a pair of shoes lie in the interval
[80,180] dollars.
Delivery fee 20% of price.
i.e. delivery fee will be in the interval [4, 9]
(1/20th of price)
Total cost= price of shoedelivery cost
Hence f(c) = c+c/20 = 21c/20
The domain of this function would be c lying between 80 to 180
So domain =[80,180]
---------------------------------
Amount to be repaid = 42 dollars
Once he received this amount, the price would be
105+42 =147
But since price range is only [21*80/20, 21*180/20]
=[84, 189]
Since now Albert has 147 dollars, he can afford is
[80,147]