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3 years ago

9

Draw the image of quadrilateral ABCD under a translation by 2 units to the left and 6 units down.

1 answer:

12345 [234]3 years ago

5 0

A=(3,-4)
B=(-2,-6)
C=(-3,-3)
D=(-1,-5)

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The equation of a circle is ( x - 3) 2 + ( y + 2) 2 = 25. The point (8, -2) is on the circle.

Shtirlitz [24]

Answer:

x =8 is the equation of the tangent.

Step-by-step explanation:

Here the equation of the given circle is: $(x-3)^{2} + (y+2)^{2} = 25$

Now, comparing it with the general equation of circle: $(x-h)^{2} + (y -k)^{2} = r^2$

we get the central coordinates (h,k) = (3,-2)

So, the slope of the line joining center and (8, -2) = $\frac{-2 -(-2)}{8-3} = \frac{0}{5} = 0$

Since the slope of line = 0, line is parallel to x axis.

Now, as tangent and the line is perpendicular to each other

⇒Slope of the tangent = -1/ slope of the line = $\frac{-1}{0}$

Now, by point slope formula: the equation of the tangent is

(y-y0) = m (x-x0)

or, $(y +2) = \frac{-1}{0} (x -8)$

or x =8 is the equation of the tangent.

8 0

3 years ago

a point on a perpendicular bisector is 7cm from each endpoint of the bisected segment and 5cm from the point of intersection. Wh

love history [14]

9514 1404 393

Answer:

about 9.80 cm

Step-by-step explanation:

The length of half the segment (h) can be found from the Pythagorean theorem:

h² +5² = 7²

h² = 7² -5² = 49 -25 = 24

h = √24 = 2√6

This is half the segment length, so the whole segment length is ...

L = 2h = 2(2√6)

L = 4√6 ≈ 9.7980

The length of the segment is 4√6 ≈ 9.80 cm.

8 0

3 years ago

Help vvvvvvvvvvvvvvvvvvv

kvv77 [185]

I think C would be it

3 0

3 years ago

Help find the distance between two points?

miv72 [106K]

Answer:

4

Step-by-step explanation:

Calculate the distance using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = B(0, 0) and (x₂, y₂ ) = ( $\frac{\sqrt{6} }{2}$ , $\frac{\sqrt{58} }{2}$ )

AB = $\sqrt{((\frac{\sqrt{6} }{2})^2 }$ + $\{(\frac{\sqrt{58} }{2})^2 }$

= $\sqrt{\frac{6}{4} }$ + $\frac{58}{4}$

= $\sqrt{\frac{64}{4} }$

= $\sqrt{16}$

= 4

7 0

4 years ago

−7x−50≤−1 AND−6x+70>−2

fgiga [73]

Answer:

$-7\geq x$ and $[-7,12)$ in interval notation.

Step-by-step explanation:

We have been given a compound inequality $-7x-50\leq -1\text{ and }-6x+70>-2$ . We are supposed to find the solution of our given inequality.

First of all, we will solve both inequalities separately, then we will combine both solution merging overlapping intervals.

$-7x-50\leq -1$

$-7x-50+50\leq -1+50$

$-7x\leq 49$

Dividing by negative number, flip the inequality sign:

$\frac{-7x}{-7}\geq \frac{49}{-7}$

$x\geq -7$

$-6x+70>-2$

$-6x+70-70>-2-70$

$-6x>-72$

Dividing by negative number, flip the inequality sign:

$\frac{-6x}{-6}$

$x$

Upon merging both intervals, we will get:

$-7\geq x$

Therefore, the solution for our given inequality would be $-7\geq x$ and $[-7,12)$ in interval notation.

7 0

4 years ago