Answer:
1.1
Step-by-step explanation:
7.2-6.1
Answer:
Step-by-step explanation:
24,000 = 24 thousands
30,000 = 30 thousands
3,000 = 3 thousands
2,4000 = 2.4 thousands
"x" years
24 + 3x = 30 + 2.4x
3x - 2.4x = 30 - 24
0.6x = 6
x = <em>10 years</em>
Answer:
Alternate interior
Answer:
Step-by-step explanation:
( 2 , 26 )
( 0 , 4 )
m = (26 - 4 ) / ( 2 - 0 ) = 11
Cost of each game is $11
![\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to &\$500\\ r=rate\to 6\%\to \frac{6}{100}\to &0.06\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semi-annually, thus twice} \end{array}\to &2\\ t=years\to &2 \end{cases} \\\\\\ A=500\left(1+\frac{0.06}{2}\right)^{2\cdot 2}\implies A=500(1.03)^4\implies A=562.754405](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%20%5Ctextit%7BCompound%20Interest%20Earned%20Amount%7D%0A%5C%5C%5C%5C%0AA%3DP%5Cleft%281%2B%5Cfrac%7Br%7D%7Bn%7D%5Cright%29%5E%7Bnt%7D%0A%5Cquad%20%0A%5Cbegin%7Bcases%7D%0AA%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%0AP%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cto%20%26%5C%24500%5C%5C%0Ar%3Drate%5Cto%206%5C%25%5Cto%20%5Cfrac%7B6%7D%7B100%7D%5Cto%20%260.06%5C%5C%0An%3D%0A%5Cbegin%7Barray%7D%7Bllll%7D%0A%5Ctextit%7Btimes%20it%20compounds%20per%20year%7D%5C%5C%0A%5Ctextit%7Bsemi-annually%2C%20thus%20twice%7D%0A%5Cend%7Barray%7D%5Cto%20%262%5C%5C%0At%3Dyears%5Cto%20%262%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0AA%3D500%5Cleft%281%2B%5Cfrac%7B0.06%7D%7B2%7D%5Cright%29%5E%7B2%5Ccdot%202%7D%5Cimplies%20A%3D500%281.03%29%5E4%5Cimplies%20A%3D562.754405)
now, "A" is the accumulated amount, including the earned interest, how much interest was it earned? well, is just A - P.