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1 answer:
Answer:
in triangle ABD
x+6+2x-3+90=180(sum of interior angle of triangle) (since each angle of rectangle=90)
3x+3=180-90
3x=90-3
x=87/3=29°
<DBC=<ADB{ALTERNATE ANGLE)=2x-3=2×29-3=55°
<BDC=ABD(ALTERNATE ANGLE)=x+6=29+6=35°
<ADH=180-<ADB{LINEAR PAIR)=180-2x-3=180-2×29-3=180-58-3=119°
<EBG=<DBC(VERTICALLY OPPOSITE ANGLE)=55°
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