Let the second score = x
⇒ second score = x
<span>the first is 14 points more than the second
</span>⇒ first score = x + 14
<span>the sum of the first two is 6 more than twice the third
</span>⇒ third score = 1/2 (x + x + 14 - 6) = x + 4
<span>The sum of a student's three score is 246
</span>⇒ x + (x + 14) + (x + 4) = 246
<span>
Solve x:
</span>x + x + 14 + x + 4 = 246
3x + 18 = 246
3x = 228
x = 76
second score = x = 76
first score = x + 14 = 76 + 14 = 90
Answer: 90
Step-by-step explanation:
=f³+11×g-4×h
=3³+11×2-4×7
=27+22-28
=21
is yr answer.
Try using fraction, i think the ans is 28/205 ;)
Answer: 17.75
Step-by-step explanation:
The interquartile range(IQR) is the 3rd quartile - the 1st quartile.
How to get quartiles:
First get the median:
3.5, 10.4, 16, 21.7, 27.7
10.4, 16, 21.7
16
Then find the median of the first half of data(3.5, 10.4)
(3.5+10.4)/2 = 6.95
Then find the median of the last half of data(21.7, 27.7)
(21.7+27.7)/2 = 24.7
Then to get the IQR subtract 6.95 from 24.7 to get 17.75
Hope it helps <3
