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Dafna1 [17]
3 years ago
14

Prove that if triangle ABC and triangle DEF are triangles with equal defects and a pair of congruent sides, their associated Sac

cheri quadrilaterals are congruent. (HINT: Recall that the angle sum for a triangle is equal to the sum of the measures of the summit angles of its associated Saccheri quadrilateral and that the two summit angles of a Saccheri quadrilateral are congruent.)
Mathematics
1 answer:
Nadya [2.5K]3 years ago
5 0

Answer:

According to theorem 7.5

Π ABB'A' ≅ Π DEE'D'  

therefore by transitivity of equivalence  it is proven that triangle ABC and triangle DEF are triangles with equal defects and a pair of congruent sides

Step-by-step explanation:

To prove that triangle ABC and triangle DEF are triangles with equal defects and a pair of congruent sides :

Assume:  б(Δ ABC ) =  б(Δ DEF ) and also AB ≅ DE

let Π ABB'A' and DEE'D' be taken as the saccheri quadrilaterals that corresponds to Δ ABC and Δ DEF  respectively

Following the Lemma above; б(Π ABB'A' ) = б( Π DEE'D' ) given that

AB = summit of ABB'A' and DE = summit of DEE'D'  also  AB ≅ DE

According to theorem 7.5

Π ABB'A' ≅ Π DEE'D'  

therefore by transitivity of equivalence  it is proven that triangle ABC and triangle DEF are triangles with equal defects and a pair of congruent sides

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What are the possible numbers of positive, negative, and complex zeros of f(x) = −3x4 + 5x3 − x2 + 8x + 4?
ale4655 [162]

Answer:

Either:  1 neg, 3 pos, 0 imaginary; 1 neg, 1 pos, 2 imaginary

Step-by-step explanation:

Look for the positive possibilities first.  Count the numbe of sign changes then subtract 2, if possible, as many times as you can.

There are 3 sign changes.  So the possible positive roots are either 3 or 1.

Now look for the negative possibilities.  Replace each x with a -x and then count the sign changes.  Replacing with -x's gives you this polynomial:

f(-x)=-3x^4-5x^3-x^2-8x+4

There is only one sign change here, so the possible negative roots is 1.  Start with the negative roots to find the possible combinations of positive, negative, and imaginary, since there is only 1.

-     1       1

+    3       1

i     0       2

Since this is a 4th degree, the number of roots we have has to add up to equal 4.

8 0
3 years ago
Tell me which option is correct: (0,m) (b,0) (m,0) (0,b) which one of those
strojnjashka [21]

Answer:

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Search for questions & chapters

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Class 11

>>Physics

>>Units and Measurement

>>Errors in Measurement

>>You measure two quantities ...

Question

Bookmark

You measure two quantities as A=1.0m±0.2m, B=2.0m±0.2m. We should report correct value for

AB

as

Medium

Solution

verified

Verified by Toppr

Correct option is

D

1.4m±0.2m

Here, A=1.0m±0.2m, B=2.0m±0.2m

AB=(1.0m)(2.0m)=2.0m

2

AB

=

2.0m

=1.414m

Rounding off to two significant figures, we get

AB

=1.4m

AB

ΔAB

=

2

1

(

A

ΔA

+

B

ΔB

)=

2

1

(

1.0

0.2

+

2.0

0.2

)=

2

0.3

Δ

AB

=

2

0.3

×

AB

=

2

0.3

×1.414=0.212m

Rounding off to one significant figure, we get

Δ

AB

=0.2m

The correct value for

AB

is 1.4m±0.2m

8 0
2 years ago
Using the graph , determine the coordinates of the vertex of the parabola
aivan3 [116]

Answer:

(-4,-4)

Step-by-step explanation:

Delta math

3 0
2 years ago
PLEASE HELP!!!!! 2.) What is the perimeter of a polygon with vertices at (-3, 1), (5, 1), (-3, 4), (5, 4)? 30 points if you can
vredina [299]

Answer:

22 units

Step-by-step explanation:

Known Quantities:

  • AB = CD and AC = BD

Calculations:

  • AB = 8
  • AC = 3
  • CD = 8
  • BD = 3

Final Calculations:

  • perimeter = 2 x (3+8)
  • perimeter = 22

4 0
2 years ago
HELP!!!!!! I believe its B but I am not sure! :(
n200080 [17]

Answer:

A

Step-by-step explanation:

When solving for x as an exponent, we need to use logarithms in order to undo the operation and rearrange the terms. We use log rules to bring down the exponent and solve. Logarithms are the inverse operations to exponents and vice versa. We have one special kind of logarithm called the natural logarithm whose base is e. We write it as ln. Since our base is e here, we will use the natural logarithm to rearrange and isolate x.

e^{4x-1} =3

We begin by applying the natural logarithm to each side.

ln(e^{4x-1}) =ln(3)

Log rules allow use to rearrange the exponent as multiplication in front of the log.

(4x-1)ln(e) =ln(3)

ln e as an inverse simplifies to 1.

(4x-1)(1)=ln(3)

We now apply the inverse operations for subtraction and multiplication.

4x-1+1=1+ln(3)\\4x=1+ln(3)\\\frac{4x}{4} =\frac{1+ln3}{4} \\x =\frac{1+ln3}{4}

Option A is correct.

5 0
3 years ago
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