Answer:
Either: 1 neg, 3 pos, 0 imaginary; 1 neg, 1 pos, 2 imaginary
Step-by-step explanation:
Look for the positive possibilities first. Count the numbe of sign changes then subtract 2, if possible, as many times as you can.
There are 3 sign changes. So the possible positive roots are either 3 or 1.
Now look for the negative possibilities. Replace each x with a -x and then count the sign changes. Replacing with -x's gives you this polynomial:

There is only one sign change here, so the possible negative roots is 1. Start with the negative roots to find the possible combinations of positive, negative, and imaginary, since there is only 1.
- 1 1
+ 3 1
i 0 2
Since this is a 4th degree, the number of roots we have has to add up to equal 4.
Answer:
search-icon-header
Search for questions & chapters
search-icon-image
Class 11
>>Physics
>>Units and Measurement
>>Errors in Measurement
>>You measure two quantities ...
Question
Bookmark
You measure two quantities as A=1.0m±0.2m, B=2.0m±0.2m. We should report correct value for
AB
as
Medium
Solution
verified
Verified by Toppr
Correct option is
D
1.4m±0.2m
Here, A=1.0m±0.2m, B=2.0m±0.2m
AB=(1.0m)(2.0m)=2.0m
2
AB
=
2.0m
=1.414m
Rounding off to two significant figures, we get
AB
=1.4m
AB
ΔAB
=
2
1
(
A
ΔA
+
B
ΔB
)=
2
1
(
1.0
0.2
+
2.0
0.2
)=
2
0.3
Δ
AB
=
2
0.3
×
AB
=
2
0.3
×1.414=0.212m
Rounding off to one significant figure, we get
Δ
AB
=0.2m
The correct value for
AB
is 1.4m±0.2m
Answer:
(-4,-4)
Step-by-step explanation:
Delta math
Answer:
22 units
Step-by-step explanation:
Known Quantities:
Calculations:
Final Calculations:
- perimeter = 2 x (3+8)
- perimeter = 22
Answer:
A
Step-by-step explanation:
When solving for x as an exponent, we need to use logarithms in order to undo the operation and rearrange the terms. We use log rules to bring down the exponent and solve. Logarithms are the inverse operations to exponents and vice versa. We have one special kind of logarithm called the natural logarithm whose base is e. We write it as ln. Since our base is e here, we will use the natural logarithm to rearrange and isolate x.

We begin by applying the natural logarithm to each side.

Log rules allow use to rearrange the exponent as multiplication in front of the log.

ln e as an inverse simplifies to 1.

We now apply the inverse operations for subtraction and multiplication.

Option A is correct.