Answer:
`The answer is below
Step-by-step explanation:
P and q are points on the line y=2-4X. complete the coordinates of P and Q, P(0, ) Q( ,0)
Draw the line y= 2-4X for vales of x from -2 to 2
Solution:
The equation of a line is given by:
y = mx + b
Where y and x are variables, m is the slope of the line and b is the y intercept (that is value of y when x = 0).
The line of y = 2 - 4x is drawn by finding the corresponding values of y for x from -2 to 2 and plotting on a graph.
x: -2 -1 0 1 2
y: 10 6 2 -2 -6
The value P(0, ) Q( ,0)
The y coordinate of point P is gotten by substituting x = 0:
y = 2 - 4(0) = 2
P = (0, 2)
The x coordinate of point Q is gotten by substituting y = 0:
0 = 2 - 4x
4x = 2
x = 0.5
Q = (0.5, 0)
First is -1 and 4, second should be no solution and the third is 2 and 6
Answer: after 3 days
Step-by-step explanation: Step-by-step explanation: The sister has to pay rent which is $60 which means she has negative $30 in three days the sister would have earned $60 and in 3 days the brother would have earned $60
The question is:
Check whether the function:
y = [cos(2x)]/x
is a solution of
xy' + y = -2sin(2x)
with the initial condition y(π/4) = 0
Answer:
To check if the function y = [cos(2x)]/x is a solution of the differential equation xy' + y = -2sin(2x), we need to substitute the value of y and the value of the derivative of y on the left hand side of the differential equation and see if we obtain the right hand side of the equation.
Let us do that.
y = [cos(2x)]/x
y' = (-1/x²) [cos(2x)] - (2/x) [sin(2x)]
Now,
xy' + y = x{(-1/x²) [cos(2x)] - (2/x) [sin(2x)]} + ([cos(2x)]/x
= (-1/x)cos(2x) - 2sin(2x) + (1/x)cos(2x)
= -2sin(2x)
Which is the right hand side of the differential equation.
Hence, y is a solution to the differential equation.
12 - b = -2
12 + 2 = b
14 = b
