Question

Question 13 of 46 What is the remainder for the synthetic division problem below?

Answer 1

Answer:

Step-by-step explanation:

Let's do this out as best as we can here. Here's the problem:

2 |  3   1   2   -7

___________

The rule is to bring down the first term, whatever it is (ours is a 3), and multiply it by the number "outside" which is a 2. Put that product up under the number next to the 3:

2 |  3   1   2   -7

          6          

    3

Then add straight down, and multiply that sum by the 2 outside and put that product under the next number (the 2 "inside" the box):

2 |  3   1   2   =7

          6  14      

     3   7

And do the same thing. Add straight down, multiply the sum by 2 and put the product up under the next number, -7, and add again. The final is shown below:

2 |  3     1     2     -7

            6   14     32

    3      7    16    25

The last number in the very bottom row, the depressed polynomial row, is the remainder. Ours is a 25. This is the super easy way to divide polynomials, as long as our divisor is a linear (first degree) term.