Answer:
9
Step-by-step explanation:
We are given that a spinner is divided into three equal section labeled 1,2 and 3.
Another spinner is divided into four equal sections labeled W,X,Y and Z.
We have to find the number of possible outcomes have an odd number or an X.
Sample space ={(1,W),(1,Y),(1,X),(1,Z),(2,W),(2,X),(2,Y),(2,Z),(3,W),(3,X),(3,Y),(3,Z)}
Number of outcomes in which an odd number or an X
={(1,X),(3,X},{1,W),(1,Y),(1,Z),(3,Y),(3,W),(3,Z),(2,X)}
Hence, number of possible outcomes have an odd number or an X=9