Answer:
D^2 = (x^2 + y^2) + z^2
and taking derivative of each term with respect to t or time, therefore:
2*D*dD/dt = 2*x*dx/dt + 2*y*dy/dt + 0 (since z is constant)
divide by 2 on both sides,
D*dD/dt = x*dx/dt + y*dy/dt
Need to solve for D at t =0, x (at t = 0) = 10 km, y (at t = 0) = 15 km
at t =0,
D^2 = c^2 + z^2 = (x^2 + y^2) + z^2 = 10^2 + 15^2 + 2^2 = 100 + 225 + 4 = 329
D = sqrt(329)
Therefore solving for dD/dt, which is the distance rate between the car and plane at t = 0
dD/dt = (x*dx/dt + y*dy/dt)/D = (10*190 + 15*60)/sqrt(329) = (1900 + 900)/sqrt(329)
= 2800/sqrt(329) = 154.4 km/hr
154.4 km/hr
Step-by-step explanation:
Answer:
<h2><u>
2x+6</u></h2>
Step-by-step explanation:
2(x+3)
=(2)(x+3)
=(2)(x)+(2)(3)
=2x+6
Slope=3, Y-intercept=(0,-1)
Answer:
-2
Step-by-step explanation:
-5 + 3 = -2
If you have any questions about the way I solved it, don't hesitate to ask me in the comments below :)
There are 6 nickels and 14 pennies.
There are 20 total coins.
The ratio of nickels to coins is 6:20.
Both of these are divisible by 2, so we can reduce this to 3:10.
