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2 years ago

−1/3−(−1/2)

Mathematics

1 answer:

Radda [10]2 years ago

6 0

Hi ;-)

$-\frac{1}{3}-(-\frac{1}{2})=-\frac{1}{3}+\frac{1}{2}=-\frac{2}{6}+\frac{3}{6}=\frac{3}{6}-\frac{2}{6}=\frac{1}{6}\\\\3\frac{1}{3}-5=-(5-3\frac{1}{3})=-(4\frac{3}{3}-3\frac{1}{3})=-1\frac{2}{3}\\\\-1\frac{4}{5}-(-2\frac{7}{8})=-1\frac{4}{5}+2\frac{7}{8}=-1\frac{32}{40}+2\frac{35}{40}=2\frac{35}{40}-1\frac{32}{40}=1\frac{3}{40}\\\\-3\frac{3}{8}-\frac{7}{8}=-(3\frac{3}{8}+\frac{7}{8})=-3\frac{10}{8}=-3\frac{5}{4}=-4\frac{1}{4}\\\\4\frac{3}{4}-(-1\frac{1}{12})=4\frac{9}{12}+1\frac{1}{12}=5\frac{10}{12}$

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Determine the margin of error for a 90% confidence interval to estimate the population mean when s = 40 for the sample sizes bel

Ann [662]

Answer:

a) The margin of error for a 90% confidence interval when n = 14 is 18.93.

b) The margin of error for a 90% confidence interval when n=28 is 12.88.

c) The margin of error for a 90% confidence interval when n = 45 is 10.02.

Step-by-step explanation:

The t-distribution is used to solve this question:

a) n = 14

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 14 - 1 = 13

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 13 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.9}{2} = 0.95$ . So we have T = 1.7709

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 1.7709\frac{40}{\sqrt{14}} = 18.93$

In which s is the standard deviation of the sample and n is the size of the sample.

The margin of error for a 90% confidence interval when n = 14 is 18.93.

b) n = 28

27 df, T = 1.7033

$M = T\frac{s}{\sqrt{n}} = 1.7033\frac{40}{\sqrt{28}} = 12.88$

The margin of error for a 90% confidence interval when n=28 is 12.88.

c) The margin of error for a 90% confidence interval when n = 45 is

44 df, T = 1.6802

$M = T\frac{s}{\sqrt{n}} = 1.6802\frac{40}{\sqrt{45}} = 10.02$

The margin of error for a 90% confidence interval when n = 45 is 10.02.

3 0

3 years ago

Suppose a jar contains 5 red marbles and 25 blue marbles. If you reach in the jar and pull out one marble at random, do not repl

dsp73

Answer:

Probability that event will have both red marbles will be 2.3% or 0.023.

Step-by-step explanation:

Given:

Total red marbles=5

Total blue marbles=25

Total number of marbles =30

To Find:

The probability that both are red without replacement of marbles.

Solution:

Now

Total sample space is 30 and total red marbles are 5

For a event that getting red marble probability is ,

=Total red marbles /total marbles.

=5/30

=1/6

So probability if getting red marble is 1/6

<em>Now for second chance there will be 4 red marbles remaining and 29 total marbles so,</em>

In second chance probability if getting red marble will be

=total red marbles present/total marbles remaining

=4/29

Now ,

The required probability will be getting both at a time

i.e probability getting red AND red marble so here AND operator which means multiple both the probability.

Probability both will have red =1/6*4/29

=4/(29*6)=2/(29*3)

=0.022988

=0.023

=2.3 %

8 0

3 years ago

A straight line has gradient -2 and passes through the point (-3 , 10).

Aleksandr-060686 [28]

Answer:

y = 4 - 2x

Step-by-step explanation:

That is the formula, in y = a + mx but it you want it in y = mx+c, it is y = -2x + 4

8 0

2 years ago

If m= 8, how many solutions are there for the expression m - 8?

saw5 [17]

Step-by-step explanation:

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3 years ago

Which of the following examples illustrates ordinal numbers?

Margaret [11]

Answer:

30-5×2 of 3+(19-3) ÷8

Step-by-step explanation:

30-5×6+(19-3)÷8

30-5×6+16÷8

30-30+8

38-30

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2 years ago