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olya-2409 [2.1K]
2 years ago
11

Please can some one solve this for me thankyou :-) its sudoku

Mathematics
1 answer:
Paraphin [41]2 years ago
8 0

 

In the .docx file is a SUDOKU that needs to be resolved.

See the solution in the attached image.

   

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Why is it that -log(x+8)=4-log(x-7) has no solution? (they are log base 2)
Lerok [7]
-log(x+8)=4-log(x-7) 

-\log _{10}\left(x+8\right)+\log _{10}\left(x+8\right)=4-\log _{10}\left(x-7\right)+\log _{10}\left(x+8\right) 

0=4-\log _{10}\left(x-7\right)+\log _{10}\left(x+8\right) 

0+\log _{10}\left(x-7\right)=4-\log _{10}\left(x-7\right)+\log _{10}\left(x+8\right)+\log _{10}\left(x-7\right) 

\log _{10}\left(x-7\right)=\log _{10}\left(x+8\right)+4 

\log _{10}\left(x-7\right)=\log _{10}\left(x+8\right)+\log _{10}\left(10000\right) 

x-7=\left(x+8\right)\cdot \:10000 

\mathrm{Solve\:}\:x-7=\left(x+8\right)10000:\quad x=-\dfrac{26669}{3333} 

\mathrm{Verifying\:Solutions}:\quad x=-\dfrac{26669}{3333}\space\mathrm{False} 

\mathrm{No\:Solution\:for\:x\in \mathbb{R}}
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3 years ago
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torisob [31]

Answer:

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Step-by-step explanation:

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Use the triangle to answer the question. What is the value of x?
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Answer:

B). 48

Step-by-step explanation:

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3 years ago
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Connecticut families were asked how much they spent weekly on groceries. Using the following data, construct and interpret a 95%
Amanda [17]

Answer:

The 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

Step-by-step explanation:

The data for the amount of money spent weekly on groceries is as follows:

S = {210, 23, 350, 112, 27, 175, 275, 50, 95, 450}

<em>n</em> = 10

Compute the sample mean and sample standard deviation:

\bar x =\frac{1}{n}\cdot\sum X=\frac{ 1767 }{ 10 }= 176.7

s= \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }       = \sqrt{ \frac{ 188448.1 }{ 10 - 1} } \approx 144.702

It is assumed that the data come from a normal distribution.

Since the population standard deviation is not known, use a <em>t</em> confidence interval.

The critical value of <em>t</em> for 95% confidence level and degrees of freedom = n - 1 = 10 - 1 = 9 is:

t_{\alpha/2, (n-1)}=t_{0.05/2, (10-1)}=t_{0.025, 9}=2.262

*Use a <em>t</em>-table.

Compute the 95% confidence interval for the population mean amount spent on groceries by Connecticut families as follows:

CI=\bar x\pm t_{\alpha/2, (n-1)}\cdot\ \frac{s}{\sqrt{n}}

     =176.7\pm 2.262\cdot\ \frac{144.702}{\sqrt{10}}\\\\=176.7\pm 103.5064\\\\=(73.1936, 280.2064)\\\\\approx (73.20, 280.21)

Thus, the 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

7 0
3 years ago
30 points<br> Picture attached
Reika [66]
What is the problem cause i dont see a photo

7 0
3 years ago
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