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Hoochie [10]
3 years ago
5

What is the solution to the absolute value inequality?

Mathematics
1 answer:
Sloan [31]3 years ago
4 0
Answer -  c </= 4 or c >/= -3
2c - 1 </ 7
2c - 1 + 1 </= 7 +1
2c </= 8
2c/2  </=   8/2
c </=  4
2c - 1 >/= - 7
2c - 1 + 1 >/=  -7 + 1
2c  >/=  -6
2c/2  >/=  -6/2
c  >/=  -3
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Is 2×3×4the prime factorization of 24 Explain you reasoning​
Elden [556K]

Answer:

see the prime factors

Step-by-step explanation:

24= 6*4=3*2*2*2

=2*3*4

6 0
3 years ago
Read 2 more answers
Pls help me!! I just need help on both of the following questions, a-d on each
Ymorist [56]
I'll do a and e on the first one to show you how to do it

Then See if you can do the rest

a. 6(-3)<span><span>
</span></span>
When your multiplying or dividing with negative numbers; If one of your numbers is negative like the one above, your answer will be negative

So 6 × 3 = 18 ; but since there is a negative on the 3 your answer will be -18

e. -20 ÷ 5

same for this; 20 ÷ 5 = 4, but since the 20 is negative the answer will be <span>-4

You do b, c, d, and f on the first question. Tell me what you get and we'll go from there

</span>Now for the second question <span>

</span>I will do a and d to show you how to do this then you do the rest<span> (I'm inserting a picture with these)

</span>a. 4(-2 \frac{1}{3}) + 7 \frac{1}{6}
First go ahead and turn the fractions into improper fractions, this makes them a bit easier to work with. When multiplying fractions; they do not need a common denominator, all you do is multiply top by top and bottom by bottom.<span>
However, when you add and subtract fractions you MUST have a common denominator

</span>d. (-4.25)(2) + (-4.25)(-2)
remember from the first problem a negative times a positive gives you a negative<span>

but when you times a negative by a negative you get a positive


Now you try b and c; let me know what you get, and we'll go from there!

</span>

7 0
3 years ago
Rectangle A measures 10 inches by 8 inches. Rectangle B is an enlarged copy of Rectangle A. Select all of the measurement pairs
Fudgin [204]

Answer:

See Explanation

Step-by-step explanation:

Given

Rectangle A:

Length: 10\ in

Width: 8\ in

Required

Determine the possible dimensions of Rectangle B

<em>The question has missing options; however, the question can still be solved.</em>

<em></em>

Rectangle B being an enlarged copy of A implies that the dimension of A A is enlarged in equal proportion to form B

Take for instance, the measurements of Rectangle B are

Length: 15 in

Width: 12 in

Divide the corresponding lengths of B by A to get the enlargement ratio

Ratio = \frac{B}{A}

For length:

Ratio = \frac{15}{10}

Ratio = 1.5

For width

Ratio = \frac{12}{8}

Ratio = 1.5

Notice that both ratios are the same.

For this measurement of B, we can conclude that B is an enlargement of A

Assume another measurements for B

Length: 20\ in

Width: 10\ in

Calculate Ratios

Ratio = \frac{B}{A}

For length:

Ratio = \frac{20}{10}

Ratio = 2

For width

Ratio = \frac{10}{8}

Ratio = 1.25

Notice that, both ratios are not equal.

For this measurement of B, we can conclude that B is not an enlargement of A

<em>Conclusively, all you have to do is: determine the ratios of the dimensions of B to A, if the result are equal then B is an enlarged copy of A; if otherwise, then B is not an enlarged copy</em>

5 0
3 years ago
1) A family consisting of three persons—A, B, and C—goes to a medical clinic that always has a doctor at each of stations 1, 2,
crimeas [40]

Answer:

Step-by-step explanation:

Let us record the station number 1, 2 or 3 for each family member A, B or C.

I am attaching a table containing total outcomes. Outcomes are presented along rows while the assigned station to each member is written along columns. For ease of understanding, 1 3 2 in the table should be interpreted as family member A being assigned to station 1, member B to station 3 and member C to station number 2, respectively.

From table it is clear that the total outcomes possible are 27.

We know that, probability can be defined as,

PROBABITILY = \frac{NUMBER\;OF\;DESIRED\;OUTCOMES}{TOTAL\;NUMBER\;OF\;OUTCOMES}

a) All Members Assigned to the Same Station.

Cases for all members being assigned to same station are as follows:

[1 1 1], [2 2 2], [3 3 3] (outcome number 1, 14 and 27 in the table).

Therefore,

PROBABILITY\;(Case\;a) = \frac{3}{27}\\\\PROBABILITY\;(Case\;a) = 0.111

b) At Most Two Members Assigned to the Same Station.

It means that maximum of 2 members can have the same station. Cases for this situation are as follows:

[1 1 2], [1 1 3], [1 2 1], [1 2 2], [1 3 1], [1 3 3], [2 1 1], [2 1 2], [2 2 1], [2 2 3], [2 3 2],

[2 3 3], [3 1 1], [3 1 3], [3 2 2], [3 2 3], [3 3 1], [3 3 2]

(outcome number 2, 3, 4, 5, 7, 9, 10, 11, 13, 15, 17, 18, 19, 21, 23, 24, 25 and 26 in the table).

Therefore,

PROBABILITY\;(Case\;b) = \frac{18}{27}\\\\PROBABILITY\;(Case\;b) = 0.666

c) All Members Assigned to a Different Station.

For this scenario, we have the following results:

[1 2 3], [1 3 2], [2 1 3], [2 3 1], [3 1 2], [3 2 1] (outcome number 6, 8, 12, 16, 20 and 22 in the table).

Therefore,

PROBABILITY\;(Case\;c) = \frac{6}{27}\\\\PROBABILITY\;(Case\;c) = 0.222

3 0
3 years ago
George, the ginger cat weighs 14 pounds. His pal, lgor weighs 6 pounds. How much more does george weigh than lgor
Masja [62]

Answer:

8.!..!.!?!.!..¿? your welcome;)

4 0
2 years ago
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