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g100num [7]
3 years ago
7

Simplify the expression. 3.6 - 3.1n -2n + 5

Mathematics
2 answers:
Marina CMI [18]3 years ago
5 0

Answer:

-5.1n+8.6 plz give brainliest

Step-by-step explanation:

MrRa [10]3 years ago
5 0
-5.1n + 8.6 all you need to do is add like terms hope this helped pls give me branliest
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the length of the sides of a square are initially 0 cm and increase at a constant rate of 11 cm per second. suppose the function
Likurg_2 [28]

The function of the area of the square is A(t)=121t^{2}

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

\frac{dx}{dt} = 11 \frac{cm}{sec}

⇒x=11t

Area of square=(length of side)^{2}

Area of square=(11t)^{2}{as the length of side is 11t}{varies by time}

Area of square=121t^{2}

Therefore,The function of the area of the square is A(t)=121t^{2}

Learn more about The function of the area of the square is A(t)=121t^{2}

Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area

Lets assume the length of side of square is x

\frac{dx}{dt} = 11 \frac{cm}{sec}

⇒x=11t

Area of square=(length of side)^{2}

Area of square=(11t)^{2}{as the length of side is 11t}{varies by time}

Area of square=121t^{2}

Therefore,The function of the area of the square is A(t)=121t^{2}

Learn more about area here:

brainly.com/question/27683633

#SPJ4

3 0
2 years ago
You purchased 18.000 milliliters of juice. Juice costs $2 per liter. The cashier
Aleonysh [2.5K]

Answer:

cashier needed to divide by 1000, not 3.

Step-by-step explanation:

there are 1000ml in one liter. in order to find the amount of liters, youd have to divide the milliliters by 1000. its only after then that you can multiply by $2. answer would be $36

6 0
2 years ago
Solve the system of equations. y = 2x y = x 2 – 15
inn [45]

Answer:

D. (–3, –6) and (5, 10)

Step-by-step explanation:

The system has equations:

y=2x...(1)

and

y=x^2-15...(2)

Equate both equations;

x^2-15=2x

Rewrite in standard form:

x^2-2x-15=0

We factor to obtain:

(x+3)(x-5)=0

By the zero product principle;

(x+3)=0,(x-5)=0

\implies x=-3,x=5

When x=-3, y=2(-3)=-6

This yields the ordered pair (-3,-6).

When x=5, y=2(5)=10

This yields the ordered pair (5,10).

The correct choice is D.

8 0
3 years ago
2. It’s time for Ronda to start repaying her student loans, which are amortized over the next 10 years. Her first month’s paymen
grigory [225]

Based on the amount that she paid in the first month, the amount Ronda will pay for the next month is<u> $396.</u>

When a loan is amortized, it means that one can pay it off by paying the same amount every period until they would have paid off both the loan and the associated interest.

The amortized amount contains:

  • A portion going towards the principal(debt )
  • A portion going towards the interest accumulated.

In conclusion, as the amount is the same every time, Ronda will have to pay the same amount of $396 the next month.

<em>Find out more at brainly.com/question/12256592. </em>

7 0
3 years ago
Good x sold for $40 in 1945. the Cpi in 1945 was 18.0 and the cpi in 1999 was 166.6. what was the price of good x in 1999 dollar
andrey2020 [161]

Answer:

the price of good x in 1999 dollars is 370.89 dollars

Step-by-step explanation:

Given that good x sold for $40 in 1945. the Cpi in 1945 was 18.0 and the cpi in 1999 was 166.6.

We have cpi and sale price have direct variation

In other words S = kC where C = CPi and S = sales price

In 1945, 40 = 18k or K = 20/9

Using this we can say

Sales price in 1999 would be k (166.6)

=\frac{20}{9} (166.6)\\= 370.89

the price of good x in 1999 dollars is 370.89 dollars

5 0
3 years ago
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