Find the exact value of sec 3pi/2 If not defined, write undefined.
1 answer:
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Answer:
Step-by-step explanation:
I figured this out with calculus since it's easier that way. The position function for the ball is
. The first derivative of position is velocity, so we need to find the first derivative of the position function which is
v(t) = -32t + 64
Now, where the ball is at its highest point is where the velocity is equal to 0, so setting the velocity function equal to 0 allows us to determine how many seconds it takes to get to that max height.
0 = -32t + 64 and
-64 = -32t so
t = 2 seconds. It takes 2 seconds to get to its max height. In order to determine that max height, we sub 2 in for t in the position function:
and
s(2) = 66 feet. The max height of the ball is 66 feet.
Answer:
y = 4x +5
Slope is 4
Intercept is 5
Step-by-step explanation:
Using, y1= 1 and x1= -1
And, y2 = 13, x2 = 2
y-1 = 4x +4
y = 4x +4 +1 = 4x +5