The rectangle below has an area of zº +82 + 15 square meters and a width of 2 + 3 meters.
1 answer:
Answer:
(x + 5) m
Step-by-step explanation:
From the question given above, the following data were obtained:
Area (A) = (x² + 8x + 15) m²
Width (W) = (x + 3) m
Length (L) =?
The lenght of the rectangle can be obtained as follow:
A = L × W
x² + 8x + 15 = L (x + 3)
Divide both side by x + 3
L = x² + 8x + 15 / x + 3
L = (x + 5) m
Please attached photo for explanation.
Therefore, the length of the rectangle is: (x + 5) m
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Answer:
(C)72.4 in
Step-by-step explanation:
Given an acute triangle in which the longest side measures 30 inches; and the other two sides are congruent.
Consider the attached diagram
AB=BC=x
However to be able to solve for x, we form a right triangle with endpoints A and C.
Since the hypotenuse is always the longest side in a right triangle
Hypotenuse, AC=30 Inches
Using Pythagoras Theorem
Therefore, the smallest possible perimeter of the triangle
Perimeter=2x+30
=2(21.21)+30
=42.42+30
=72.4 Inches (rounded to the nearest tenth)
