The rectangle below has an area of zº +82 + 15 square meters and a width of 2 + 3 meters.
1 answer:
Answer:
(x + 5) m
Step-by-step explanation:
From the question given above, the following data were obtained:
Area (A) = (x² + 8x + 15) m²
Width (W) = (x + 3) m
Length (L) =?
The lenght of the rectangle can be obtained as follow:
A = L × W
x² + 8x + 15 = L (x + 3)
Divide both side by x + 3
L = x² + 8x + 15 / x + 3
L = (x + 5) m
Please attached photo for explanation.
Therefore, the length of the rectangle is: (x + 5) m
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Answer:
Our equation for the height is:
y(t) = 275 - 16*t^2.
a) To find the average velocity between two times, t1 and t2, (where t2 > t1) the equation is:
Then:
i) t1 = 4s, t2 = 4s + 0.1s = 4.1s
The average velocity is:
And the units will be ft/s, so the average speed is:
-129.6 ft/s
The minus sign is because te pebble is falling down.
ii) t1 = 4s, t2 = 4s + 0.05s = 4.05s
The average velocity is:
So the average speed is -128.9 ft/s
iii) t1 = 4s, t2 = 4s + 0.01s = 4.01s
The average speed is:
The average speed is -128.16 ft/s.
b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.
v(t) = dy(t)/dt.
v(t) = -2*16*t + 0
Then the velocity at t = 4s is:
v(4s) = -32*4 = -128
The instantaneous velocity at t = 4s is -128 ft/s.