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rosijanka [135]
3 years ago
9

A​ 12-sided die is rolled. The set of equally likely outcomes is​ {1,2,3,4,5,6,7,8,9,10,11,12}. Find the probability of rolling

a number greater than 2.
Mathematics
1 answer:
vfiekz [6]3 years ago
3 0

Answer:

Probability of rolling a number greater than 2 = 5/6

Step-by-step explanation:

Given:

Number;

1,2,3,4,5,6,7,8,9,10,11,12

Find:

Probability of rolling a number greater than 2

Computation:

Number greater than 2 = 10

Probability of rolling a number greater than 2 = Number greater than 2 / Total number

Probability of rolling a number greater than 2 = 10 /12

Probability of rolling a number greater than 2 = 5/6

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Grace [21]
3x^2-(-2x^2)+5x-(-6x)-6-(7)=5x^2+11x\text{ - 13}

Therefore, the correct answer is:

2)5x^2+11x\text{ - 13}

5 0
1 year ago
The diameter of a cylindrical construction pipe is 4ft If the pipe is 17ft long, what is its volume? Use the value 3.14 for /pi,
Leya [2.2K]

Answer:

213.52 cubic ft

Step-by-step explanation:

Diameter of pipe = 4ft

radius for circle is half of diameter

thus radius of pipe = 1/2 of 4ft = 2 ft

length of pipe = 17 feet

volume of cylinder is given by \pi r^2l

where r is the radius and l is the length of cylinder

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thus volume of pipe is calculated below using above values

volume \ of \ pipe = \pi r^2l\\volume \ of \ pipe = \3.14* 2^2*17 \\volume \ of \ pipe =  213.52

volume of pipe is 213.52 cubic ft.

5 0
3 years ago
Which quantity is proportional to 20/5?
kirza4 [7]

Answer:

100/25, 60/15, and 4/1

Step-by-step explanation:

4 0
3 years ago
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Describe the rotation of J
Serga [27]

Answer:

The coordinates of J' when rotating by 90° counterclockwise will be: J'(3, 1)

The coordinates of J' when rotating by 90° clockwise will be: J'(-3, -1)

Step-by-step explanation:

Square JKLM with vertices

  • J(1, -3)
  • K(5, 0)
  • L(8, -4)
  • M(4, -7)

We have to determine the answer for the image J' of the point (1, -3) when we rotate the point by 90° counterclockwise, we need to switch x and y, make y negative.

In other words, the rule to rotate a point by 90° counterclockwise.

P(x, y) → P'(-y, x)

As we are given that J(1, -3), so the coordinates of J' will be:

J(1, -3) → J'(3, 1)

Therefore, the coordinates of J' when rotating by 90° counterclockwise will be:  J'(3, 1).

When the point is rotated by 90° clockwise, we need to switch x and y, make x negative.

In other words, the rule to rotate a point by 90° clockwise.

P(x, y) → P'(y, -x)

As we are given that J(1, -3), so the coordinates of J' will be:

J(1, -3) → J'(-3, -1)

Therefore, the coordinates of J' when rotating by 90° clockwise will be:  J'(-3, -1)

3 0
3 years ago
Solve the inequality for x: -3(2x+5) < -45
balandron [24]

Answer:

x>5

Step-by-step explanation:

-3(2x+5)<-45

2x+5<-45/-3

2x+5<15

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2x<10

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x<5

x>5

7 0
3 years ago
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