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3 years ago

Draw a number line that shows numbers larger than 2 and smaller than 5. Please visualize your thinking!

Mathematics

1 answer:

Pani-rosa [81]3 years ago

6 0

Answer:

Here it is. Hope it helped. Apart from 3, 4 is also a number.

plz mark me as brainliest.

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A bag contains 4 blue marbles, 6 red marbles, 3 yellow marbles, and 5 black marbles. What is the probability that you choose two

Ronch [10]

Answer:

.065

Step-by-step explanation:

The total number of marbles is

4 blue marbles+ 6 red marbles+ 3 yellow marbles+5 black marbles=18

P(1st black) = Black/total = 5/18

You keep the marble

The total number of marbles is

4 blue marbles+ 6 red marbles+ 3 yellow marbles+4 black marbles=17

P(2st black) = Black/total = 4/17

Multiply the probabilities together

P(black,black)= 5/18 * 4/17 =10/153=.065359477 =.065

4 0

3 years ago

An ice cream shop has 5 flavors. Carlos wants to buy a five-scoop cone with 5 different flavors. How many cones could he buy if

icang [17]

I think the answer is E

3 0

3 years ago

Is it weird to date someone older than u?

natulia [17]

Answer:

no its not

Step-by-step explanation:

5 0

3 years ago

PLEASE HELP ME WITH BOTH QUESTIONS<br> THANKS!!

vitfil [10]

First one:

cos(A)=AC/AB=3/4.24

cos(B)=BC/AB=3/4.24

Cos(A)/cos(B)=AC/AB / (BC/AB) = AC/AB * AB/BC = AC/BC=3/3=1

Second one:

To solve this problem, we have to ASSUME AFE is a straight line, i.e. angle EFB is 90 degrees. (this is not explicitly given).

If that's the case, AE is a transversal of parallel lines AB and DE.

And Angle A is congruent to angle E (alternate interior angles).

Therefore sin(A)=sin(E)=0.5

8 0

3 years ago

According to the National Center for Health Statistics, in 1990, 28% of babies in the United States were born to parents who w

svlad2 [7]

Answer:

The year is $b = 1995$

Step-by-step explanation:

From the question we are told that

The percentage of the number of babies born out of wedlock in 1990 is k = 28%

The percentage by which the number increase per year is i = 0.6%

The percentage of of the number of babies born out of wedlock considered is a = 31%

Generally the difference in between the percentage in 1990 and the percentage considered is

$d = a - k$

=> $d = 31 - 28$

=> $d = 3\%$

Generally the number of year require for the percentage to be equal to 31% is mathematically represented as

$n = \frac{3\%}{0.6\%}$

=> $n = 5\ years$

Generally the year which the considered percentage will be attained is

$b = 1990 + n$

=> $b = 1990 + 5$

=> $b = 1995$

6 0

3 years ago