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masya89 [10]
2 years ago
9

Use the relationships in the diagram to find the value of C 520 d 379 63

Mathematics
1 answer:
Brut [27]2 years ago
7 0

Answer:

c = 154°

Step-by-step explanation:

I Hope this helps.

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Last one anyone that can help me out?
Usimov [2.4K]

Answer:

Part a. t = 7.29 years.

Part b. t = 27.73 years.

Part c. p = $3894.00

Step-by-step explanation:

The formula for continuous compounding is: A = p*e^(rt); where A is the amount after compounding, p is the principle, e is the mathematical constant (2.718281), r is the rate of interest, and t is the time in years.

Part a. It is given that p = $2000, r = 2.5%, and A = $2400. In this part, t is unknown. Therefore: 2400 = 2000*e^(2.5t). This implies 1.2 = e^(0.025t). Taking natural logarithm on both sides yields ln(1.2) = ln(e^(0.025t)). A logarithmic property is that the power of the logarithmic expression can be shifted on the left side of the whole expression, thus multiplying it with the expression. Therefore, ln(1.2) = 0.025t*ln(e). Since ln(e) = 1, and making t the subject gives t = ln(1.2)/0.025. This means that t = 7.29 years (rounded to the nearest 2 decimal places)!!!

Part b. It is given that p = $2000, r = 2.5%, and A = $4000. In this part, t is unknown. Therefore: 4000 = 2000*e^(2.5t). This implies 2 = e^(0.025t). Taking natural logarithm on both sides yields ln(2) = ln(e^(0.025t)). A logarithmic property is that the power of the logarithmic expression can be shifted on the left side of the whole expression, thus multiplying it with the expression. Therefore, ln(2) = 0.025t*ln(e). Since ln(e) = 1, and making t the subject gives t = ln(2)/0.025. This means that t = 27.73 years (rounded to the nearest 2 decimal places)!!!

Part c. It is given that A = $5000, r = 2.5%, and t = 10 years. In this part, p is unknown. Therefore 5000 = p*e^(0.025*10). This implies 5000 = p*e^(0.25). Making p the subject gives p = 5000/e^0.25. This means that p = $3894.00(rounded to the nearest 2 decimal places)!!!

4 0
3 years ago
Assume that there are 2 trials.
vampirchik [111]
Answer: The p(success) = 0.6

Your question is a little unclear, but I believe you are asking about the probability that at least one of the trials in the experiment were successful.

If that is the case, you simply have to add the probability of 1 success with the probability of 2 successes.

That is 0.48 +  0.16 = 0.64

Rounding our answer to one decimal place gives us 0.6.
7 0
3 years ago
Read 2 more answers
Identify the exponential function for the given graph.
Korolek [52]

Answer:

Step-by-step explanation:

C - 3(2^x).

8 0
3 years ago
[IMPORTANT PLEASE READ!!] I am currently at home, I'm in summer school for Algebra 1. I'm taking a pre-test, once I finish this
Llana [10]
<h2>Answer:</h2>

The vertex of the function is:

                             (-2,-2)

<h2>Step-by-step explanation:</h2>

We are given a absolute value function f(x) in terms of variable "x" as:

                       f(x)=-|x+2|-2

We know that for any absolute function of the general form:

f(x)=a|x-h|+k

the vertex of the function is : (h,k)

and if a<0 the graph of function opens downwards.

and if a>0 the graph of the function opens upwards.

Hence, here after comparing  the equation with general form of the equation we see that:

a= -1<0 , h= -2 and k= -2

Since a is negative , hence, the graph opens down .

         Hence, the vertex of the function is:

                         (-2,-2)

3 0
3 years ago
Read 2 more answers
The heights (in inches) and pulse rates (in beats per minute) for a sample of 40 women were measured. Using technology with the
Viktor [21]

Answer:

There is not sufficient evidence  to support the claim that there is a linear correlation between the heights and pulse rates of women

Step-by-step explanation:

The correlation coefficient between the variables h(height in inches) and pulse rates (in beats per minute) is 0.202

Sample size n=40

Level of significane alpha = 0.01

Create null and alternate hypothesis as:

H0: r=0

Ha: r not equal 0

(Two tailed test at 1% significance level)

Sample r = 0.202

r difference = 0.202

test statistic t = \frac{r\sqrt{n-2} }{\sqrt{1-r^2} } \\=\frac{0.202(\sqrt{38} )}{\sqrt{0.9592} } \\=\frac{1.25}{0.9794} \\=1.271

df =n-2 =38

t critical value for 0.01 and df =38 is 2.704

Since our test statistic lies below 2.704, we accept null hypothesis

There is not sufficient evidence  to support the claim that there is a linear correlation between the heights and pulse rates of women

7 0
3 years ago
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