Answer:
Step-by-step explanation:
A set of normally distributed data has a mean of 3.2 and a standard deviation of 0.7. Find the probability of randomly selecting 30 values and obtaining an average greater than 3.6.
We can denote the population mean with the symbol 
According to the information given, the data have a population mean:
.
The standard deviation of the data is:
.
Then, from the data, a sample of size 
is taken.
We want to obtain the probability that the sample mean is greater than 3.6
If we call
to the sample mean then, we seek to find:
To find this probability we find the Z statistic.
Where:
Where 
is the standard deviation of the sample
Then:
The probability sought is: 
When looking in the standard normal probability tables for right tail we obtain:
Answer:
8, 9, 10, 11, 12
Step-by-step explanation:
Consecutive integer problems are often easier to work if you consider average values. Here, the middle of the 5 consecutive integers is their average, which is 50/5 = 10.
This tells you the integer side lengths are 8, 9, <em>10</em>, 11, 12.
Answer:
3/4
Step-by-step explanation:
2/3 = 4/6 so 5/6 plus 4/6 = 1 3/6 then divide by 2, it will give u 0.75 in decimal form which is simplifyed to 3/4, so 3/4 is the answer.
.008<.01
The further the number gets from the decimal point, the smaller the number is. The number closest to the decimal point dictates whether the number is bigger or smaller than the other number. For example, .090001 is still greater than .0009999, since the nine is closer to the decimal.
