Zaynab decides to put £3000 in a bank account which pays 5% compound interest per year.

Mathematics

2 answers:

andrew11 [14]3 years ago

8 0

Interest rates during the 8 years will be = 1200£

3000-1200=1800 left

storchak [24]3 years ago

4 0

Balance would be 1,800

You might be interested in

There are 13 teams of cheerleaders at a competition. The order of performance is determined at random. What is the probability t

PIT_PIT [208]

probability of you performing first is 1/13

after your team performs there are 12 teams left, so chance of the other team performing next is 1/12

chance of both happening = 1/13 * 1/12 = 1/156

3 0

4 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :