131.25 miles.
If 1 inch actually equals 25 inches, then you can just multiply 5.25 inches by 25, and because 1 in is equivalent to 25 miles, then your final answer will be in miles
Answer:
Simplifying
3.2 = 2y
Solving
3.2 = 2y
Solving for variable 'y'.
Move all terms containing y to the left, all other terms to the right.
Add '-2y' to each side of the equation.
3.2 + -2y = 2y + -2y
Combine like terms: 2y + -2y = 0
3.2 + -2y = 0
Add '-3.2' to each side of the equation.
3.2 + -3.2 + -2y = 0 + -3.2
Combine like terms: 3.2 + -3.2 = 0.0
0.0 + -2y = 0 + -3.2
-2y = 0 + -3.2
Combine like terms: 0 + -3.2 = -3.2
-2y = -3.2
Divide each side by '-2'.
y = 1.6
Simplifying
y = 1.6
Step-by-step explanation:
Answer:
The price will be increased at a rate of 1.05 everyweek to keep my revenue constant.
Step-by-step explanation:
Since demand is dropping at a rate of 4 per week, my next week sales will be (80cups - 4cups = 76cups).
Therefore in order to keep weekly revenue constant I'll have to increase my selling price.
Present revenue = 80cups * 40¢ =3200¢
For my nextweek revenue which will be ( 80-4=76 cups) to be at the same 3200¢, I'll use:
Let X be the new price per cul
[ 3200¢ = X * 76]
X= 3200¢/76
X = 42.11¢
Which means I'll need to sell at a rate of 42.11¢ per the next week to keep my revenue the same.
To get the rate [42.11¢ / 40¢ = 1.05]
That means I will be increasing at a rate of 1.05 everyweek to keep my revenue constant.
Answer:
<em>x2 + 8x – 65 = 0</em>
Step-by-step explanation:
Complete question
<em>A square picture with a side length of 4 inches needs to be enlarged. The final area needs to be 81 square inches. Which equation can be used to solve for x, the increase in side length of the square in inches? x2 + 4x – 81 = 0 x2 + 4x – 65 = 0 x2 + 8x – 65 = 0 x2 + 8x – 81 = 0</em>
Given the initial side length = 4in
Initial area = L²
L is side length of the square
Initial area = 4²
Initial area = 16 square inches
Area of the enlarged square = 81 square inches
To get the constant term of the expression, we will find the difference in the areas
Difference = 85 - 16
Difference = 65 square units
The coefficient of x will be the 2 *initial area of the square
Given the standard form of an expression as
ax^2 + bx + c
a = 1, b = 2*4 = 8, c = -65
Substitute
x^2 + 8x - 65
This gives the required expression
