Answer:
I believe it might be 2over 6
Step-by-step explanation:
my guess but it might be wrong or right i dont know
DR/dt= -5inM-¹
dH/dt = 5inM-¹
recall V=πr²h
dV/dr = 2πrh
dV/dh= πr²
dV/dt = ½{ (dH/dt • dV/dH) + (dV/dr • dr/dt)}
dV/dt = ½{ ( 5×πr²) + (2πrh×-5)}
dV/dt = ½{ 5πr² -10πrh}
= ½{ 80π - 120π}
= -20π inM-¹
Answer:
(0, 6), (4, 4), and (0, -4)
Step-by-step explanation:
basically you pick 2 sides (each with endpoints at two of the three verticies) to be the adjacent sides, and then you can easily find the fourth vertex for each case.