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3 years ago

Race to get brainliest, need help!

Mathematics

2 answers:

Gemiola [76]3 years ago

7 0

Answer:

Original number is 86

Step-by-step explanation:

Original: 10x + y

Double reversed: 2(10y + x)

Constraints:

x + y = 14 ===> x = 14 - y

2(10y + x) + 10x + y = 222 ===> 21y + 12x = 222

Substitution to find y:

21y + 12x = 222

21y + 12(14 - y) = 222

21y + 168 - 12y = 222

9y + 168 = 222

9y = 54

y = 6

Substitution to find x:

x = 14 - y

x = 14 - 6

x = 8

Original: 10x + y

10(8) + (6)

80 + 6

Sophie [7]3 years ago

4 0

X = Tens place
y = Ones place
x+y=14
y=14-x
2(10y+x)+(10x+y)=222
20y+2x+10x+y=222
21y+12x=222
21(14-x)+12x=222
294-21x+12x=222
-9x = -72
x = 8
y = 14-8 =6
ANSWER: 86

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Priya spent 1/2 of the day hiking. She was lost 5/6 of the time that she was hiking. What fraction of the day was Priya lost

Vadim26 [7]

Answer:

$\frac{5}{12}$ fraction of the day was Priya lost

Step-by-step explanation:

As per the statement:

Priya spent 1/2 of the day hiking.

⇒She spent for hiking = 1/2 of the day.

It is also given that:

She was lost 5/6 of the time that she was hiking.

⇒ $\text{She lost} = \frac{5}{6} \times \text{She was hiking}$

Substitute the given values we have;

$\text{She lost} = \frac{5}{6} \times \frac{1}{2} = \frac{5}{12}$ of the day

therefore, $\frac{5}{12}$ fraction of the day was Priya lost

5 0

3 years ago

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Yuki888 [10]

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3 years ago

Which expression is equivalent to

True [87]

Answer:

$2^{\frac{5}{12}}$

Step-by-step explanation:

The original expression $\sqrt{2^5} ^{\frac{1}{4}}$ can be transformed into $(2^{\frac{5}{3}})^{\frac{1}{4}}$ : both expressions are equivalent, the root of certain number is equivalent to that number power at a fraction whose denominator is the index of the root. The simpliest example for this statement is $\sqrt{x} =x^{\frac{1}{2}}$ (the squared root of x equals x raised at 1/2).
Now, the expression $(2^{\frac{5}{3}})^{\frac{1}{4}}$ can be simplified by using the power of a power property, which simply states that if $b\neq 0$ and $((b)^n)^m=b^{n\times{m}}$ . In this case, then $(2^{\frac{5}{3}})^{\frac{1}{4}}=2^{\frac{5}{3}\times{\frac{1}{4}}}=2^{\frac{5}{12}}$ , which is the final expression.