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Hunter-Best [27]
3 years ago
15

Find the missing length.

Mathematics
1 answer:
Ivahew [28]3 years ago
7 0

Answer:

hello,

Step-by-step explanation:

12²=(x-16)*16

9=x-16

x=25

Relation metric in a right triangle

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I've been on this question for 15 min..... please help
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I believe the answer would be no
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Which polynomial correctly combines the like term and express the given polynomial in standard form
ankoles [38]

Answer:

8mn^5 - 2m^6 + 5m^2n^4 - m^3n^3 + n^6 - 4m^6 + 9m^2n^4 - mn^5 - 4m^3n^3 = -6m^6  - mn^5 - 5m^3n^3 + 14m^2n^4 + 8mn^5  + n^6

Step-by-step explanation:

Given

8mn^5 - 2m^6 + 5m^2n^4 - m^3n^3 + n^6 - 4m^6 + 9m^2n^4 - mn^5 - 4m^3n^3

Required

Correctly combine the like terms

We have:

8mn^5 - 2m^6 + 5m^2n^4 - m^3n^3 + n^6 - 4m^6 + 9m^2n^4 - mn^5 - 4m^3n^3

Collect like terms (in decreasing degrees of m)

- 2m^6 - 4m^6  - mn^5- m^3n^3  - 4m^3n^3+ 5m^2n^4  + 9m^2n^4 + 8mn^5  + n^6

-6m^6  - mn^5 - 5m^3n^3 + 14m^2n^4 + 8mn^5  + n^6

So:

8mn^5 - 2m^6 + 5m^2n^4 - m^3n^3 + n^6 - 4m^6 + 9m^2n^4 - mn^5 - 4m^3n^3 = -6m^6  - mn^5 - 5m^3n^3 + 14m^2n^4 + 8mn^5  + n^6

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3 years ago
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4 years ago
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3 years ago
What is wrong with the equation? 2 x−3 dx = x−2 −2 2 −3 = − 5 72 −3 f(x) = x−3 is continuous on the interval [−3, 2] so FTC2 can
Wewaii [24]

Answer:

Hello your question is incomplete below  is the complete question

What is wrong with the equation? integral^2 _3 x^-3 dx = x^-2/-2]^2 _3 = -5/72 f(x) = x^-3 is continuous on the interval [-3, 2] so FTC2 cannot be applied. f(x) = x^-3 is not continuous on the interval [-3, 2] so FTC2 cannot be applied. f(x) = x^-3 is not continuous at x = -3, so FTC2 cannot be applied The lower limit is less than 0, so FTC2 cannot be applied. There is nothing wrong with the equation. If f(2) = 14, f' is continuous, and f'(x) dx = 15, what is the value of f(7)? F(7) =

answer : The value of f(7) = 29

Step-by-step explanation:

Attached below is the detailed solution

Hence : F(7) - 14 = 15

F(7) = 15 + 14 = 29

8 0
4 years ago
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