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Basile [38]
3 years ago
13

Please answer the question that is in the photo attached below

Mathematics
2 answers:
rewona [7]3 years ago
4 0

Answer:

\huge\boxed{b=\sqrt{7}}

Step-by-step explanation:

In order to solve for this equation we have to note a couple of things.

There is a diagonal square inside a larger square. The space formed by the smaller square not being in the larger square is a right triangle.

The side length of the smaller square (4) is also the hypotenuse of this triangle.

Since we know that the other side length of the triangle is 3, we can use the Pythagorean Theorem to find the value of b.

The Pythagorean Theorem states that a^2 + b^2 = c^2, where a and b are the legs and c is the hypotenuse.

We can substitute 3 in as a and 4 in as c and find b.

3^2 + b^2 = 4^2

9+b^2=16

b^2=7

b = \sqrt{7}

So b is \sqrt{7} units long.

Hope this helped!

sweet [91]3 years ago
4 0

Answer:

7

Step-by-step explanation:

Use Pythagorean Theorem:

A² + B² = C²

3² + B² = 4²

9 + B² = 16

B² = 7

B = √7

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Option A: \frac{1}{3} is the dilation factor

Explanation:

The Coordinates of the square ABCD are A(-21,18), B(-12,18), C(-12,9), D(-21,9)

Also, the coordinates of the square A'B'C'D' are A'(–7, 6), B'(-4,6), C'(-4,3), D'(-8,3)

Now, we shall determine the scale factor in the dilation if the coordinates A' and C'.

Since, the dilation is the enlargement of the image in the same shape but different size.

To determine the scale factor, let us divide A'C' by AC

Thus, we have,

\begin{aligned}A^{\prime} C^{\prime} &=\sqrt{(-4+7)^{2}+(3-6)^{2}} \\&=\sqrt{3^{2}+(-3)^{2}} \\&=\sqrt{9+9} \\&=\sqrt{18}\\&=3\sqrt{2} \end{aligned}

Also,

\begin{aligned}A C &=\sqrt{(-12+21)^{2}+(9-18)^{2}} \\&=\sqrt{9^{2}+(-9)^{2}} \\&=\sqrt{81+81} \\&=\sqrt{162}\\&=9\sqrt{2} \end{aligned}

Dividing A'C' by AC, we have,

\frac{A'C'}{AC} =\frac{3\sqrt{2} }{9\sqrt{2}} =\frac{1}{3}

Thus, \frac{1}{3} is the dilation factor

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