I don't remember the names of the theorems at all, but we know that AD ≈ DE ≈ EB (Segment Addition). Which means <ACD ≈ <DCE ≈ <ECB (not completely sure how to prove this). Therefore, <1 ≈ <2. (Don't forget to state that <1 ≈ <ACD and <2 ≈ <ECB). With this and Angle Addition, we know that <ACE ≈ <DCB, so with SAS Congruence Theorem, we can prove ΔACE ≈ ΔBCD.
Hope that helps
The triangle is not a right angle
AC = 22 - 8 - 5 = 9
AC² = AB² + BC²
81 = 64 + 25
81 isn't equal to 89, the triangle is not a right angle
X = -1
(-1, -5) The line is horizontal.
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Answer:
Louis is correct
Step-by-step explanation:
we know that
When multiplying two powers that have the same base, you can add the exponents
so
so
In this problem we have
therefore
Louis is correct
