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vichka [17]
3 years ago
11

HELP!!

Mathematics
1 answer:
algol [13]3 years ago
7 0
With the given conditions you should construct no traingle because it is scalene
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A positive real number is 2 more than another. If the sum of the squares of the two numbers is 42, find the numbers.
Brilliant_brown [7]

Answer:

Step-by-step explanation:

From the first sentence x (the number) is 2 more than another number (y). So, x+2=y. The sum of the squares of the two numbers is 42, meaning that \\ (x+2)^{2}+y^{2}=42. First, we square root the ENTIRE equation to get rid of the square. If you do one thing to one side, you have to do it to the other. After this, we have x+2+y=\sqrt{42}. Now, we subtract 2 from the other side to isolate the variable. You can isolate either one but normally I go for x. Now we have x+y=\sqrt{42}+2. Now, we want to get y to the other side so we subtract it from the left side and the right side which gives us x=-y+\sqrt{42}+2. now we know what X is equal to. Now we plug in x for \\ (x+2)^{2}+y^{2}=42, which gives us          (-y+\sqrt42}+2+2)^{2}+y^{2}=42. Now we only have one variable which is what we want. Next, we square root the entire thing to get rid of the squares, which gives us -y+\sqrt{42}+4+y=\sqrt{42}. I got lost in my work. I must have done something wrong I cant find out. If anyone wants to pick up where I left off go ahead but there's a timer and I have one minute left. I cant finish the problem in a minute. I'm sorry and hopefully I lead you somewhere.

6 0
2 years ago
I need help with question 1b
Lunna [17]

5 + 10 + 12 = 27 scores are less than 3

8 0
3 years ago
Read 2 more answers
Factor the GCF: 28a^3b^4 + 20a^2b^2 − 16ab^3.
9966 [12]
D. 4ab(7a^2b^3+5a-4b^3)
7 0
3 years ago
This question has three parts. Answer the parts in order.
nalin [4]

Answer:

The area of the smallest section is A_{1}=100yd^{2}

The area of the largest section is A_{2}=625yd^{2}

The area of the remaining section is A_{3}=250yd^{2}

Step-by-step explanation:

Please see the picture below.

1. First we are going to name the side of the larger square as x.

As the third section shares a side with the larger square and the four sides of a square are equal, we have the following:

- Area of the first section:

A_{1}=10yd*10yd

A_{1}=100yd^{2}

- Area of the second section:

A_{2}=x^{2} (Eq.1)

- Area of the third section:

A_{3}=width*length

A_{3}=10yd*x (Eq.2)

2. The problem says that the total area of the enclosed field is 975 square yards, and looking at the picture below, we have:

A_{1}+A_{2}+A_{3}=975yd^{2}

Replacing values:

100+x^{2}+10x=975

Solving for x:

x^{2}+10x-875=0

x=\frac{-10+\sqrt{100+(4*875)}}{2}

x=\frac{-10+\sqrt{3600}}{2}

x=\frac{-10+60}{2}

x=25

3. Replacing the value of x in Eq.1 and Eq.2:

- From Eq.1:

A_{2}=25^{2}

A_{2}=625yd^{2}

- From Eq.2:

A_{3}=10*25

A_{3}=250yd^{2}

3 0
3 years ago
A car that is traveling from one city to another has a velocity that is increasing at a constant slope of 3. If the car started
Masteriza [31]

Answer:

c is the answer

Step-by-step explanation:

It is the only graph  that starts at (1,0)

and if you look closely the slope is 3

3 0
3 years ago
Read 2 more answers
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