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Zigmanuir [339]
3 years ago
8

What is the area of triangle ABC?

Mathematics
1 answer:
bixtya [17]3 years ago
7 0
The answer is 30 units :))))))))
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A towing company charges a flat fee of $50 in addition to $2 a mile to tow vehicles.
olga nikolaevna [1]
Y=MX+B
Y= 2X+50
And we don’t know how long they are getting towed but when we find that out we plug it into X
4 0
3 years ago
Q # 15 I need help please to resolve
kow [346]

The sequence is

740, 707.60,675.20,642.80,...

Here first term is 740, and common difference, d is

707.60-740 = -32.40

Now we use the formula of nth term, which is

a_{n} = a+(n-1)d

Substituting the values of a,n and d, we will get

=740+(n-1)(-32.40), 23 months

Correct option is the second option .

7 0
4 years ago
-7.4 + 4.45 =<br> A 11.85<br> B 2.95<br> C -2.95<br> D -11.85
const2013 [10]
-7.4 + 4.45 = -2.95 so C
5 0
3 years ago
Read 2 more answers
In a random sample of cars driven at low altitudes, of them exceeded a standard of grams of particulate pollution per gallon of
Orlov [11]

Complete question is;

In a random sample of 370 cars driven at low altitudes, 43 of them exceeded a standard of 10 grams of particulate pollution per gallon of fuel consumed. In an independent random sample of 80 cars driven at high altitudes, 23 of them exceeded the standard. Can you conclude that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard at an level of significance? Group of answer choices

Answer:

Yes we can conclude that there is enough evidence to support the claim that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard (P-value = 0.00005).

Step-by-step explanation:

This is a hypothesis test for the difference between the proportions.

The claim is that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard.

Then, the null and alternative hypothesis are:

H0 ; π1 - π2 = 0

H1 ; π1 - π2 < 0

The significance level would be established in 0.01.

The random sample 1 (low altitudes), of size n1 = 370 has a proportion of;

p1 = x1/n1

p1 = 43/370

p1 = 0.116

The random sample 2 (high altitudes), of size n2 = 80 has a proportion of;

p2 = x2/n2

p2 = 23/80

p2 = 0.288

The difference between proportions is pd = (p1-p2);

pd = p1 - p2 = 0.116 - 0.288

pd = -0.171

The pooled proportion, we need to calculate the standard error, is:

p = (x1 + x2)/(n1 + n2)

p = (43 + 23)/(370 + 80)

p = 66/450

p = 0.147

The estimated standard error of the difference between means is computed using the formula:

S_(p1-p2) = √[((p(1 - p)/n1) + ((p(1 - p)/n2)]

1 - p = 1 - 0.147 = 0.853

Thus;

S_(p1-p2) = √[((0.147 × 0.853)/370) + ((0.147 × 0.853)/80)]

S_(p1-p2) = 0.044

Now, we can use the formula for z-statistics as;

z = (pd - (π1 - π2))/S_(p1-p2)

z = (-0.171 - 0)/0.044

z = -3.89

Using z-distribution table, we have the p-value = 0.00005

Since the P-value of (0.00005) is smaller than the significance level (0.01), then the effect is significant.

We conclude that The null hypothesis is rejected.

Thus, there is enough evidence to support the claim that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard.

6 0
3 years ago
Which ordered pair is a solutionofy=x-4
dusya [7]
X=4
y=-4
hope this helps u out :)
3 0
3 years ago
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