Answer:
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Step-by-step explanation:
If the value of variables of algebraic expression are given, the value of the term or expression can easily obtained by replacing the variables with numbers.





➝

➝

➝

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

~
its C
Step-by-step explanation:
- 2\sqrt5
this is the tan©
but you have to multiply by sqrt 5
so its become -2sqrt5/5
<u>Question 1</u>
If we let
, then
.
Also, as
bisects
, this means
.
Thus, by the intersecting chords theorem,

However, as distance must be positive, we only consider the positive case, meaning FE=9
<u>Question 2</u>
If we let CE=x, then because AB bisects CD, CE=ED=x.
We also know that since FB=17, the radius of the circle is 17. So, this means that the diameter is 34, and as AE=2, thus means EB=32.
By the intersecting chords theorem,

However, as distance must be positive, we only consider the positive case, meaning CE=8
What is the expression? Tell me and I will help you.
Answer:
the perfect cube is [A] 1