Answer:
The outer circle is 16 feet larger than the inner circle (68 - 52).
Step-by-step explanation:
Given that the inner circle circumference is 52 feet, and the distance between the inner and the outer circle is 8 feet, to determine by how many ft is the larger outer circle, the following calculation must be performed:
The radius of a circle is equal to half its diameter. Therefore, the radius of the inner circle is 26 feet. Thus, if the distance between the two circles is 8 feet, the radius of the outer circle is 34 feet (26 + 8). Therefore, the diameter of this circle is 68 feet (34 x 2).
This implies that the outer circle is 16 feet larger than the inner circle (68 - 52).
I don't know what the spaces are meant for but I think that means 934 and 6814 only. Another point is, speed should be expressed in units of distance over time. So that would be miles/min.
So, distance could be calculated by multiplying speed and time.
d = 934 mi/min * 6814 min
d = 6,364,276 miles
Answer:
14.93
Step-by-step explanation:
For this problem you need to know distance formula, which is
d=√(x2-x1)²+(y2-y1)². You'll want to plug in (0,3) and (-2, 9) and go on to plug in all of them at some point. You'll get 6.32 as the distance between (0,3) and (-2, 9), 3.61 as the distance between (-2, 9) and (-4, 6), and 5 as the distance between (-4, 6) and (0, 3). You add them up and get your answer.
Answer:
9
Step-by-step explanation:
X=Tickets bought
A=$40+$8x
B=$67+$5x
After 1 ticket bought it would be:
A=$48
B=$72
After 9 tickets bought:
A=$112
B=$112
From this you can see that Plan B is better for ones who would see 9+ movies as the recurring price would be lower. If you would only go to watch a couple movies, Plan A would be better.
Least to greatest: 20,564 22,755 2,3805