Question

Pls help pls help help pls

Answer 1

Answer:

Approximate maximum height is 5 ft

$h(\frac{18}{32} )= 5 \ ft$

Step-by-step explanation:

$h(t)=-16t^{2} + 18t$      ---------- (1)

Differentiate equation (1)  w.r.t t and equate it to zero (in order to determine maxima)

$h^{'}(t) = -32t+18$

$0= -32t+18$

$t=\frac{18}{32}$

Substitute this value in equation (1)

$h(\frac{18}{32} )=-16(\frac{18}{32} )^{2} + 18(\frac{18}{32} )$

$h(\frac{18}{32} )=-5+ 10$

$h(\frac{18}{32} )= 5 \ ft$