Answer:
a)The expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b)0.6004
c)19.607
Step-by-step explanation:
Let X denotes the number of fragments in 200 gm chocolate bar with expected number of fragments 10.2
X ~ Poisson(A) where 
a)We are supposed to find the expected number of insect fragments in 1/4 of a 200-gram chocolate bar

50 grams of bar contains expected fragments = \lambda x = 0.051 \times 50=2.55
So, the expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b) Now we are supposed to find the probability that you have to eat more than 10 grams of chocolate bar before ending your first fragment
Let X denotes the number of grams to be eaten before another fragment is detected.

c)The expected number of grams to be eaten before encountering the first fragments :
s
Answer:

Step-by-step explanation:
we know that
The formula to calculate continuously compounded interest is equal to
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
e is the mathematical constant number
we have
substitute in the formula above

Answer:
5x^2+x-6
Step-by-step explanation:
(5x-1)(x+1)-5x+x-5+x
(5x^2+5x-x-1)-5x+x-5+x
5x^2+x-6
The pattern:
So it goes, 1, 2, 3, as the first number in each equation right.
Then it goes 4,5,6 as the second number in each equation.
<span>In other words, the first number + 3 = the second number
</span>
The sum or 3rd number is a zig zag pattern from the first and second numbers as shown below.
1 2 3 4 5 6 <span>7 </span>8 9
4 <span>5 </span>6 7 8 9 10 11 <span>12
</span>
1 * 5 = 5, 2 * 6 = 12, 3 * 7 = 21 .... 8 * 12 = 96
<span>So the answer of </span><span>8+11=96</span>