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3 years ago

(6+3)-+8-7)=(1+4)+(10-8)=(3-3+(9+1)=(10-2)+(10-8)=2+(0+1+2+3)=(10-1-2-3)+4=

Mathematics

1 answer:

JulijaS [17]3 years ago

6 0

Answer:

6+3-8-7 = 8

1+4+10-8 = 7

3-3+9+1 = 10

10-2+10-8 = 10

2+0+1+2+3 = 8

10-1-2-3+4 = 8

Step-by-step explanation:

i don't know if these are supposed to be easy or not lol but thanks for the points :p

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2067 Supp Q.No. 2a Find the sum of all the natural numbers between 1 and 100 which are divisible by 5. Ans: 1050

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Answer:

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Step-by-step explanation:

Natural Numbers are positive whole numbers. They aren't negative, decimals, fractions. We can just divide 5 into 100 to find how many natural numbers go up to 100 and just add them but that is just to much.

There is a easier method.

E.g: Natural Numbers that are divisible by a Nth Number. is the same as adding the Nth Numbers to a multiple of that Nth Term. For example, let say we need to find numbers divisible by 2. We know that 4 is divisible by 2 because 4/2=2. We can add the Nth numbers which is 2 to 4. 4+2=6. And 6 is divisible by 2 because 6/2=3. We can call this a arithmetic series. A series which has a pattern of adding a common difference