Answer:
30 acres of A
0 acres of B
Step-by-step explanation:
On forming the equations we get
Acres = A+B 
30 .............(1)
Seed = 5A + 10B 200 ...........(2)
Profit = 160A+50B
Upon rearranging this we get
A= 30-B sing equation (1)
A=40-2B using equation (2)
On plotting these inequalities on the cartesian planes we will get the following points of intersection (0,20) (20,30) (30,0)
Now using these coordinates (A,B) to get Maximum profit
P= $1000 for (0,20)
P=$4700 for (20,30)
P= $4800 for (30,0)
clearly for (30,0) we will get the maximum profit on the crops
47 (numeral)
forty seven (in words)
40 + 7 (expanded form)
4 tens and 7 ones (tens and ones)
*Hope that helps XD *
Two packs of Tina with 26 + 26 = 52 oz of mayonnaise.
I hope this helped
Answer:
a. 14
b. 7
Step-by-step explanation:
a. First we must add all the animals together,
Total Animals:
Birds: 6
Fish: 5
Mammals: 11
Reptiles: 3
Therefore our equation is:
6 + 5 + 11 +3 = 25.
Now, we must subtract by the number of mammals:
25 - 11 = 14
So our answer for a. is 14!
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
b. So for this problem we must compute mammals + fish and than birds + reptiles. After we figure that out we must subtract them!
Mammals + Fish =
11 + 5 =
16
Next,
Birds + Reptiles =
6 + 3 =
9
Now, let us subtract them,
16 - 9 =
7
So our answer for b. is 7 more animals!
this gives
total area of the field = 4655 sqyrd + 1884.79 sqyrd = 6539.79 sqyrd
cost of fertilising 1 sqyrd = $ 0.08
so cost of fertilising 6539.79 sqyrd = 6539.79 * $ 0.08 = $ 523.18
