Answer:
cone volume=(1/3)hpir^2
d/2=r
d=12
d/2=12/2=6=r
V=120pi
120pi=(1/3)hpi6^2
120pi=(1/3)hpi36
120pi=12hpi
divide both sides by pi
120=12h
divide 12
10=h cm
if height and diameter is doubled aka height and radius are doubled
V=(1/3)(2h)pi(2r^2)
we want to see how it compares to V=(1/3)hpir^2
V=(1/3)(2h)pi(2r^2)
V=2(1/3)(h)pi4r^2
V=8((1/3)hpir^2)
the volume is increased by 8 times
blanks are
10
8
Step-by-step explanation:
Answer: 240
180×100=18,000
18,000÷75=240
to check
.75×240=180
I hope this is good enough:
17.5 because when you find range, you need to subtract the smallest number to the biggest number which in this case the biggest is 20 and smallest is 2.5.
Answer:
Step-by-step explanation:
<u>We know that:</u>
- Angles ∠A and ∠B are 28° and 37°.
<u>We don't know:</u>
<u>So, we do this:</u>
- Add the 180°
- Solve the equation 180 - 28 - 37
<u>Solve:</u>
Angle ∠C is 115°.
Answer:
A
Step-by-step explanation:
let y = f(x) and rearrange making x the subject, that is
y = 
( multiply both sides by x³ )
x³y = 19 ( divide both sides by y )
x³ = 
( take the cube root of both sides )
x = ![\sqrt[3]{\frac{19}{y} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B19%7D%7By%7D%20%7D)
Change y back into terms of x, then
(x) = ![\sqrt[3]{\frac{19}{x} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B19%7D%7Bx%7D%20%7D)
= ![\frac{\sqrt[3]{19} }{\sqrt[3]{x} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B19%7D%20%7D%7B%5Csqrt%5B3%5D%7Bx%7D%20%7D)
→ A
