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Citrus2011 [14]
4 years ago
5

How many multiples of 7 are there between 100 and 1000.

Mathematics
2 answers:
vivado [14]4 years ago
8 0
So after 100 its 105,112,119...........994
x=7(multiples of what we're finding), y=105(where we start from after 100), a multiplied by z=994
we have to find z

994=105+(z-1)7
994-105=7z-7
889+7=7z
896=7z
z= 128
Alex Ar [27]4 years ago
8 0
105,112,119,126,133,140,147,154,161,168,175,182,189,196,203,210,217,224,231,238,245,252,259,266,273,280,287,294,301,308,315,322,329,336,343, 350, 357, 364, 371, 378, 385, 392, 399, 406, 413, 420, 427, 434, 441, 448, 455, 462, 469, 476, 483, 490, 497, 504, 511, 518, 525, 532, 539, 546, 553, 560, 567, 574, 581, 588, 595, 602, 609, 616, 623, 630, 637, 644, 651, 658, 665, 672, 679, 686, 693, 700, 707, 714, 721, 728, 735, 742, 749, 756, 763, 770, 777, 784, 791, 798, 805, 812, 819, 826, 833, 840, 847, 854, 861, 868, 875, 882, 889, 896, 903, 910, 917, 924, 931, 938, 945, 952, 959, 966, 973, 980, 987, 994

Read more: http://www.mathwarehouse.com/arithmetic/multiple-calculator.php?#ixzz5C6UCeW5c
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The perimeter of a rectangular
cupoosta [38]

Answer:

5 ft

Step-by-step explanation:

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18 = 2(4) + 2H

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<u>5 = H</u>

I hope this helps!

7 0
3 years ago
9. If LK = MK, LK = 7x - 10. KN = x + 3, MN = 9x - 11, and KJ = 28, find LJ.<br> M<br> K<br> L<br> N
ki77a [65]
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3 years ago
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aliya0001 [1]

Answer:

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Step-by-step explanation:

4 0
4 years ago
The number of corn stalks in each row of field can be modeled by arithmetic sequence.The 5th row in this field has 36 corn stalk
Mice21 [21]

Answer:

a_{n}=20+4(n-1)

Step-by-step explanation:

It is given that the number of corn stalks in rows of the field can be modeled by an arithmetic sequence.

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a_{5}=36

The 12th row has 64 stalks. So,

a_{12}=64

In order to write the explicit rule we need to find the first term(a1) and common difference(d) of the sequence.

The explicit rule for the arithmetic sequence is of the form:

a_{n}=a_{1}+(n-1)d

Writing the 5th and 12th term in this way, we get:

a_{5}=a_{1}+4d

a_{1}+4d=36                                                     Equation 1

Similarly for 12th term, we can write:

a_{1}+11d=64                                                     Equation 2

Subtracting <u>Equation 1</u> from <u>Equation 2</u>, we get:

7d = 28

d = 4

Using the value of d in <u>Equation 1</u>, we get:

a_{1}+4(4)=36\\\\ a_{1}=20

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a_{n}=20+4(n-1)

7 0
3 years ago
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CaHeK987 [17]
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3 years ago
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