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inn [45]
3 years ago
5

Can I get some help? Thanks!

Mathematics
2 answers:
vivado [14]3 years ago
4 0

Answer:

C: y=11x

Step-by-step explanation:

11x2=22

11x3=33

11x4=44

So on and so forth.

lawyer [7]3 years ago
4 0
Answer is C, not A, B, or D.
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Identify the like terms in this expression: 4x^2 + 2x - 6x + 3y
Kamila [148]

Answer:

the like terms here are the x and the + symbol.

Step-by-step explanation:

If a part of the equation appears more than once that is a like term.

8 0
3 years ago
A motor racing circuit has length 5 5/6 miles. A straight section of the circuit has 1 1/4 miles. What fraction of the circuit i
aleksklad [387]

Answer:

3/14

Step-by-step explanation:

1 1/4 can be written as 5/4

5 5/6 can be written as 35/6

so divide (5/4)/(35/6)

= (5/4)*(6/35)

=(1/4)*(6/7)

=6/28

simplified = 3/14

4 0
3 years ago
What is the slant height x of the given pyramid to the nearest tenth
andreev551 [17]
The slant height, x, is 7.5 mm because you use the pythagorean formula and solve for c, since the you're solving for the hypotenuse which is the longest side.
4 0
3 years ago
Read 2 more answers
Find the slope of the line containing the given points
Luden [163]

Answer:

-9/8

Step-by-step explanation:

The two points given are

(1,6) and (9,-3)

The slope is given by

m = (y2-y1)/(x2-x1)

   = (-3-6)/(9-1)

   = -9/8

8 0
3 years ago
21. In the figure given below, AC is parallel to DE. Find the valuesof xy and z and hence find the 2DBE.
algol13

Answer:

X= 50°

Y= 70°

Z= 30°

BDE= 30°

2BDE= 60°

Step-by-step explanation:

(2x -70 )+z+(2x+20)=180...(sum of angle on a straight line)

2x -70 = BDE... alternate angles

Y + (2x-70)+(50+x-20) = 180...(sum of angles in a triangle)

X-20 = z ... alternate and opposite angles

(2x -70 )+z+(2x-+20)=180

2x-70 + x-20 +2x +20= 180

5x -70= 180

5x = 250

X= 50°

X-20 = z

50-20= z

30° = z

2x -70 = BDE

2(50) -70 = BDE

100-70 = BDE

30°= BDE

Y + (2x-70)+(50+x-20)

Y + 100-70 +50 +50 -20 = 180

Y + 200-90=180

Y= 70°

2BDE = 2*30

2BDE= 60°

8 0
3 years ago
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