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puteri [66]
3 years ago
7

5(2y-2)+4=4 what is y?

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
6 0
Y=1 is your answer to your problem hope i helped 
agasfer [191]3 years ago
6 0
Use distributive property to remove the parentheses.

10y - 10 + 4 = 4
     10y - 6 = 4
          10y = 4 + 6
           10y = 10
                y = 10/10
                y = 1

hope this helps :)

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What is the equation of the line that passes through (4, -1) and (-2, 3)?
inessss [21]
(4,-1),(-2,3)
slope = (3 - (-1) / (-2 - 4) = -4/6 = -2/3

y = mx + b
slope(m) = -2/3
use either of ur points...(4,-1)...x = 4 and y = -1
now sub into the formula and find b, the y int
-1 = -2/3(4) + b
-1 = -8/3 + b
-1 + 8/3 = b
-3/3 + 8/3 = b
5/3 = b
so ur equation is : y = -2/3x + 5/3
8 0
3 years ago
Read 2 more answers
Sandra wants to evaluate 2 cot Her work is shown below. What did she do wrong?
Rashid [163]

Answer: The first option.


Step-by-step explanation:

1. You need to remember that:

- An even function is a function with the following property:

f(-x)=f(x)

- An odd function  is a function with the following property:

f(-x)=-f(x)

2. By definition, the contangent is an odd function, therefore you have that:

cot(-θ)=-cot(θ)

Then:

2cot(-\frac{9\pi}{2})\neq2cot(\frac{9\pi}{2})

3. So, you can coclude that the first step is wrong. Therefore, the answer is the first option.



8 0
3 years ago
I need help please and thank you
Katarina [22]

Answer:

F- the first answer choice

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Each side of a square is increasing at a rate of 5 cm/s. at what rate is the area of the square increasing when the area of the
topjm [15]
<span>This problem is solved using the chain rule. the area of the square is f(t) and the length of the side is g(t) f(t)=g(t)^2 g'(t)=5 Using the chain rule f'(t)=2*g(t)*g'(t) The value of g(t) is sqrt(49) which is 7. g'(t) is given as 5 cm/s f'(t)=2*7*5=14*5=70cm^2/s</span>
3 0
2 years ago
Which equation is an identity?
Sav [38]

Answer:

Equation 3

Step-by-step explanation:

An identity is, simply put, an equation that is always true. 1 = 1, 2 = 2, and x = x are all examples of identities, as there's no case in which 1 ≠ 1, 2 ≠ 2, and x ≠ x. Essentially, if we can manipulate and equation so that we end up with the same value on either side, we've found an identity. Let's run through and try to solve each of these equations to see which one fulfills that condition:

8 - (6v + 7) = -6v - 1

8 - 6v - 7 = -6v - 1

1 - 6v = -6v - 1

1 = -1

This is clearly untrue. Moving on to the next equation:

5y + 5 = 5y - 6

5 = -6

Untrue again. Solving the third:

3w + 8 - w = 4w - 2(w - 4)

2w + 8 = 4w - 2w + 8

2w + 8 = 2w + 8

If we created a new variable z = 2w + 8, we could rewrite this equation as

z = z, <em>which is always true</em>. We can stop here, as we've now found that equation 3 is an identity.

4 0
3 years ago
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