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3 years ago

7

5(2y-2)+4=4 what is y?

2 answers:

Nimfa-mama [501]3 years ago

6 0

Y=1 is your answer to your problem hope i helped

agasfer [191]3 years ago

6 0

Use distributive property to remove the parentheses.

10y - 10 + 4 = 4
10y - 6 = 4
10y = 4 + 6
10y = 10
y = 10/10
y = 1

hope this helps :)

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A 22inch piece of steel is cut into three pieces so that the second piece is twice as long as the first piece, and the third pie

Dovator [93]

Answer:

<h2>The length of the pieces is 3 inch, 6 inch and 13 inch.</h2>

Step-by-step explanation:

Let, the length of the first piece is x inch.

Hence, the length of the second piece is 2x.

It is given that, the length of the third piece is one inch more than four times of the first piece. Hence, the length of the third piece is 4x + 1 inch.

The total length of the steel is 22 inch.

Hence, x + 2x + 4x + 1 = 22

or, 7x = 21

or, x = 3.

The length of the second piece is $2x = 2\times3 =$ 6 inch.

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3 years ago

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3 years ago

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Can you prove it??<br>it's hard,I tried but couldn't solve this.

BARSIC [14]

I'll abbreviate $s=\sin\theta$ and $c=\cos\theta$ , so the identity to prove is

$\dfrac{s+c+1}{s+c-1}-\dfrac{1+s-c}{1-s+c}=2\left(1+\dfrac1s\right)$

On the left side, we can simplify a bit:

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$\dfrac{1+s-c}{1-s+c}=-\dfrac{-2+1-s+c}{1-s+c}=-1+\dfrac2{1-s+c}$

Then

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So the establish the original equality, we need to show that

$\dfrac1{s+c-1}-\dfrac1{1-s+c}=\dfrac1s$

Combine the fractions:

$\dfrac{(1-s+c)-(s+c-1)}{(s+c-1)(1-s+c)}=\dfrac{2-2s}{c^2-s^2+2s-1}$

We can rewrite the denominator as

$c^2-s^2+2s-1=c^2+s^2-2s^2+2s-1$

then using the fact that $c^2+s^2=\cos^2\theta+\sin^2\theta=1$ , we get

$1-2s^2+2s-1=2s-2s^2$

so that we have

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4 years ago

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