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hichkok12 [17]
3 years ago
10

I need help with these questions. anyone down to help me ?please

Mathematics
1 answer:
charle [14.2K]3 years ago
3 0

9514 1404 393

Answer:

  • A: less than 2 hours
  • B: 2 to 5 hours
  • C: more than 5 hours

Step-by-step explanation:

The attached graph shows the various company costs for x number of hours. The graph nearest the x-axis represents the lowest cost.

We can see that cost is lowest using Company A for 2 hours or less, and Company C for 5 hours or more. For times between those, Company B has the lowest charges.

Of course, the equation for charges in each case is the sum of the service fee and the product of hourly charge and number of hours (x).

__

I find the graphing calculator to be the most efficient tool for solving these. The alternative is to compare the equations pairwise to see which gives lower rates. With a little practice, you learn that the "break even hours" will be the difference in service fees divided by the difference in hourly cost.

For example A will cost the same as B when the $20 service fee and the $10/hour cost difference are the same: for 2 hours. A and C will cost the same when the $45 service fee and the $15/hour cost difference are the same, after 3 hours. B and C will cost the same when the $25 difference in service fees and the $5/hour cost difference are the same, after 5 hours.

So B is cheaper above 2 hours, and C is cheaper than that above 5 hours. With no service fee, A is cheaper for small numbers of hours (<2).

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An airplane is flying 600 mph on a horizontal path that will take it directly over an observer. The airplane remains a constant
dezoksy [38]
<h2>Change of the distance between the observer and the airplane when X = 5 miles is 348.84 mph</h2>

Step-by-step explanation:

We have by Pythagoras theorem

       Distance between the observer and the airplane² = Horizontal distance² + Altitude²

        d² = h² + a²

Here we have

          h = X = 5 miles

          a = 7 miles

          d² = 5² + 7²  = 74

          d =8.60 miles

          \frac{dh}{dt}=600mph\\\\\frac{da}{dt}=0

Differentiating d² = h² + a² with respect to time

            2d\frac{dd}{dt}=2h\frac{dh}{dt}+2a\frac{da}{dt}\\\\8.60\frac{dd}{dt}=5\times 600+7\times 0\\\\\frac{dd}{dt}=348.84mph

Change of the distance between the observer and the airplane when X = 5 miles is 348.84 mph

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4 years ago
Questão 1
Evgesh-ka [11]

cara de culo

,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

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Find the axis of symmetry for this parabola y=-5x^2-10x-15 write it as an equation
Ksju [112]
Axis of symmetry is the x value of the vertex

the x value of the vertex, in form
y=ax^2+bx+c is -b/(2a)

so
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x value of vertex is -(-10)/(2*-5)=10/-10=-1
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Step-by-step explanation:

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