Hi so could anyone please tell me how to solve this I’ve tried looking through my notes but I can’t find a question similar to t
his I’ve even tried google but it’s no help, thank you!
1 answer:
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Answer: A) 126.6
<u>Step-by-step explanation:</u>
Since we know ∠B = 85° and ∠C = 53°, we can use the Triangle Sum Theorem (angles of a triangle = 180°) to calculate ∠A.
∠A + ∠B + ∠C = 180
∠A + 85 + 53 = 180
∠A + 138 = 180
∠A = 42
Now we have:
A = 42 B = 85 C = 53
a = 85 b = ??? c = ???
We have all of the information for ∠A and side a so we can use the Law of Sines to find b (AC).
Answer:
The length of the line segment is of 5.9 units.
Step-by-step explanation:
Distance between two points:
Suppose that we have two points, and
. The distance between these two points is given by:
How long is the line segment?
The distance between points P and Q. So
P(1,3), and Q(4,8).
The length of the line segment is of 5.9 units.
If a quadrilateral is a rhombus then:
i) all its sides have equal length,
and
ii) the 2 diagonals are perpendicular and bisect each other.
The 2 diagonals of rhombus JKLM intersect at N.
Then m(MNJ)=90°, |JN|=4 and |NM|=3 units
thus, by the Pythagorean theorem,
The perimeter of the rhombus is 4*5 units=20 units.
Answer: 20 units
i) all its sides have equal length,
and
ii) the 2 diagonals are perpendicular and bisect each other.
The 2 diagonals of rhombus JKLM intersect at N.
Then m(MNJ)=90°, |JN|=4 and |NM|=3 units
thus, by the Pythagorean theorem,
The perimeter of the rhombus is 4*5 units=20 units.
Answer: 20 units