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Korolek [52]
3 years ago
11

Complete the sentences describing glycogen breakdown. Some terms will be used more than once, and two terms will not be used at

all.
1. The enzyme ________ removes terminal glucose residues from glycogen by cleaving ________ linkages.2. Enzyme activity stops when the enzyme reaches a point _______ glucose residues from a branch point, which is a(n) ________ linkage.3. The ________ of the debranching enzymes moves three glucose residues to another branch, connecting them by a(n) ________ linkage.4. The ________ activity of the debranching enzyme removes the glucose at its ________ linkage.5. The enzyme ________ continues removing terminal glucose residuesAnswer Choices: Glucosidase, Phosphoglucomutase, three, four, glycogen phosphorylase, alpha (1,6), alpha (1,4), transferase
Biology
1 answer:
Ierofanga [76]3 years ago
8 0

Answer:

1. The enzyme __glycogen phosphorylase ______ removes terminal glucose residues from glycogen by cleaving __Alpha (1,4)______ linkages.2. Enzyme activity stops when the enzyme reaches a point __four___ glucose residues from a branch point, which is a(n) _alpha (1,6)______ linkage.3. The __transferase______ of the debranching enzymes moves three glucose residues to another branch, connecting them by a(n) __alpha(1,4)______ linkage.4. The _glucosidase_______ activity of the debranching enzyme removes the glucose at its _alpha (1,6)_______ linkage.5. The enzyme glycogen phosphorylase________ continues removing terminal glucose residuesAnswer Choices: Glucosidase, Phosphoglucomutase, three, four, glycogen phosphorylase, alpha (1,6), alpha (1,4), transferase

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En un cruce entre peces naranjas y peces grises se obtiene una generación (f1) de 50% peces grises . Realice el cruce y explique
Ilya [14]

Answer:

Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).

Explanation:

<u>Datos disponibles:</u>

  • Cruce entre peces naranjas y peces grises
  • 50% de la F1 son peces grises
  • Naranja dominante sobre gris

Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo  para color gris <em>n</em>.

Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.

Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.

Cruce:

Parental)      Nn    x     nn

Gametas)   N    n       n    n

Fenotipos) Naranja     Gris

Cuadro de Punnett)      N           n

                            n       Nn         nn

                            n       Nn         nn

F1)  2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn

     2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,    

     nn

     50% de la progenie será color naranja (Nn)

     50% de la progenie será color gris (nn)

               

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Answer:

The mass of a proton in scientific notation, is 1.67×10-27kg.

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